There are six apples, five oranges, and one pear in John's basket. His friend takes three pieces of fruit at random without r
1 answer:
Answer:
<h2>There is a 9% of chances that all three selections are apples.</h2>Step-by-step explanation:
We know that there are 6 apples, 5 oranges and 1 pear, which gives a total of 12 fruits, that's total number of possible outcomes, the denominator of the simple probability.
Now, his friend selects three fruits with three trials without replacement, that means we need to find the probability of each even and then multiply them, because they are independent events.
Notice that we calculated the total probability using the same expression. The important thing is that you need to decrease the number of events and the total number of outcomes at each selection, because after his friends picks one apple, he doesn't put it back in the bag.
Therefore, there is a 9% of chances that all three selections are apples.
(We multiplies the number by 100 to express it in percentage)
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Answer:
B
Step-by-step explanation:
One good way to look at this is to graph both polynomials, as shown in the picture. A tip to help graph is to factor it out and work from there. For example, in x²+14x+48, we can gather that (x+6)(x+8) is the same thing, and it is easier to then graph it. Similarly, for x²+12x+36, we can factor it out as (x+6)² .
When x²+12x+36 approaches 6, it is getting really close to 0, but it stays positive. When x²+14x+48 approaches 6 from the negative side, it is also getting close to 0, but it's negative. When x²+14x+48 approaches 6 from the positive side, it is positive.
Therefore, on the negative side, there is one positive and one negative (dividing a negative by a positive is negative, and a positive by a negative is also negative) , and on the positive side, there are two positives, forming one answer.The answer is therefore B
