10 is a common factor of 50 30 and 100. So is 2
Answer:
Step-by-step explanation:
Given the explicit function as
f(n) = 15n+4
The first term of the sequence is at when n= 1
f(1) = 15(1)+4
f(1) = 19
a = 19
Common difference d = f(2)-f(1)
f(2) = 15(2)+4
f(2) = 34
d = 34-19
d = 15
Sum of nth term of an AP = n/2{2a+(n-1)d}
S20 = 20/2{2(19)+(20-1)15)
S20 = 10(38+19(15))
S20 = 10(38+285)
S20 = 10(323)
S20 = 3230.
Sum of the 20th term is 3230
For the explicit function
f(n) = 4n+15
f(1) = 4(1)+15
f(1) = 19
a = 19
Common difference d = f(2)-f(1)
f(2) = 4(2)+15
f(2) = 23
d = 23-19
d = 4
Sum of nth term of an AP = n/2{2a+(n-1)d}
S20 = 20/2{2(19)+(20-1)4)
S20 = 10(38+19(4))
S20 = 10(38+76)
S20 = 10(114)
S20 = 1140
Sum of the 20th terms is 1140
Answer:
A) Akash (1.5m), Meera (1.52), Rahul (1.54m), Lakshmi (1.56m)
B) Lakshmi is the tallest, 1.56m tall
Step-by-step explanation:
Rahul- 1.54m
Akash- 1500mm
Meera- 152cm
Lakshmi- 1560mm
Let's start by converting all the measurements to meters.
Rahul is already in meters, so he can just stay the same.
1500mm = 1.5m
152cm = 1.52m
1560mm = 1.56m
So our new measurements are:
Rahul- 1.54m
Akash- 1.5m
Meera= 1.52m
Lakshmi= 1.56m
We can now make our conclusions.
A) Akash (1.5m), Meera (1.52), Rahul (1.54m), Lakshmi (1.56m)
B) Lakshmi is the tallest, 1.56m tall
Answer:
3
Step-by-step explanation:
Answer:
here is the pic you wanted
Step-by-step explanation:
