Ask question

Ask question

All categories

3 years ago

9

A prism with a volume of 270 m³ is dilated by a factor of 3. What is the volume of the dilated prism? Enter your answer in the b

ox.

2 answers:

EleoNora [17]3 years ago

7 0

A prism with a volume of 270 m³ is dilated by a factor of 3. What is the volume of the dilated prism? Enter your answer in the box.

If we dilate each dimension by 3, then the volume of the figure will be dilated by $3^{3}$ .

$3^{3}$ =3*3*3 =27

So, the volume of the dilated prism is $3^{3}$ *volume of original prism

Volume of dilated prism=27*270 $m^{3}$

Volume of dilated prism=7290 $m^{3}$

8090 [49]3 years ago

3 0

I just took the quiz the answer is 7290
I got this by doing the following 270* 3^3

You might be interested in

The height in feet of a ball dropped from a 150 ft building is given by h(t)=-16 ft^2 +150, where t is the time in seconds after

ipn [44]

Answer:

Part 1) Option A. h(2) = 86.00 means that after 2 seconds, the height of the ball is 86.00 ft

Step-by-step explanation:

we have

$h(t)=-16t^{2}+150$

where

t ----> is the time in seconds after the ball is dropped

h(t) ----> he height in feet of a ball dropped from a 150 ft

Find h(2)

That means ----> Is the height of the ball 2 seconds after the ball is dropped

Substitute the value of t=2 sec in the equation

$h(2)=-16(2)^{2}+150=86\ ft$

therefore

After 2 seconds, the height of the ball is 86.00 ft.

7 0

3 years ago

One urn contains one blue ball (labeled B1) and three red balls (labeled R1, R2, and R3). A second urn contains two red balls (R

marusya05 [52]

Answer:

(a) See attachment for tree diagram

(b) 24 possible outcomes

Step-by-step explanation:

Given

$Urn\ 1 = \{B_1, R_1, R_2, R_3\}$

$Urn\ 2 = \{R_4, R_5, B_2, B_3\}$

Solving (a): A possibility tree

If urn 1 is selected, the following selection exists:

$B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]$

If urn 2 is selected, the following selection exists:

$B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]$

<em>See attachment for possibility tree</em>

Solving (b): The total number of outcome

<u>For urn 1</u>

There are 4 balls in urn 1

$n = \{B_1,R_1,R_2,R_3\}$

Each of the balls has 3 subsets. i.e.

$B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]$

So, the selection is:

$Urn\ 1 = 4 * 3$

$Urn\ 1 = 12$

<u>For urn 2</u>

There are 4 balls in urn 2

$n = \{B_2,B_3,R_4,R_5\}$

Each of the balls has 3 subsets. i.e.

$B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]$

So, the selection is:

$Urn\ 2 = 4 * 3$

$Urn\ 2 = 12$

Total number of outcomes is:

$Total = Urn\ 1 + Urn\ 2$

$Total = 12 + 12$

$Total = 24$

5 0

3 years ago

Manuel needs to make a total of 60 deliveries this week. So far he has completed 36 of them. What percentage of his total delive

Alenkasestr [34]

Answer:

60%

Step-by-step explanation:

It’s simple

He needs to do 60, he has done 36

Percentage = (36/60) * 100

= 60%

5 0

3 years ago

Convert 2000 ft./min. to miles per hour round to the nearest 10th

Serggg [28]

Answer:

The conversion of 2000 ft per min into miles per hour is 2.268 miles per hour .

Step-by-step explanation:

Given as :

The speed = s = 2000 ft per min

Now, ∵ 5280 feet = 1 miles

so, 1 feet = $\dfrac{1}{5280}$ miles

∴ 2000 feet = $\dfrac{1}{5280}$ × 2000 miles

i.e 2000 feet = 0.378 miles

<u>Again</u>

∵ 1 minute = $\dfrac{1}{60}$ hour

So, The speed in miles per hour

s = $\dfrac{distance}{time}$

∴ s = $\frac{0.378}{\frac{1}{60}}$

i.e s = 2.268 miles per hour

Hence, The conversion of 2000 ft per min into miles per hour is 2.268 miles per hour . answer

8 0

3 years ago

The expression cos(A-B) - cos(A+B) is equal to

olchik [2.2K]

Cos (A-B) - cos (A+B)
= (cosAcosB +sinAsinB) - (cosAcosB - sinAsinB)
=2sinAsinB

Ans: 4

6 0

3 years ago

Read 2 more answers