Find the LCM of 315,420,525 using prime factorisation method with slove it

2 answers:

5 0

$\boxed{\sf \:\begin{cases}\\\begin{gathered} {\underline{{ \sf {\blue{\Large\bf \underbrace{ {\rm {\purple{\begin{array}{r | l}\large\rm{\red{ 5}}&\underline{315,420,525}\\\large\rm{\red{ 3}}& \underline{63,84,105}\\\large\rm{\red{3}}&\underline{21,28,35}\\\large\rm{\red{ 7}}&\underline{7,28,35}\\\large\rm{\red{2}}&\underline{1,4,5}\\\large\rm{\red{2}}&\underline{1,2,5}\\\large\rm{\red{5}}&\underline{1,1,5}\\&1,1,1\end{array}}}}} }}}}}\end{gathered}\\\end{cases}}$

LCM = 5 × 3 × 3 × 7 × 2 × 2 × 5

LCM = 6300

Hence, the LCM of 315 , 420 , 525 is 6300

Alona [7]3 years ago

4 0

Answer:

6300

Step-by-step explanation:

Prime factors of given numbers:

315 = 3*3*5*7
420 = 2*2*3*5*7
525 = 3*5*5*7

The LCM is:

LCM(315, 420, 525) = 2*2*3*3*5*5*7 = 6300

You might be interested in

My mom walks 1 mile in 14 minutes. If she walked for 56 minutes, how far did she walk?

marysya [2.9K]

Answer:

4 miles

Step-by-step explanation

If your mom can walk 1 mile in 14 minutes then 2 miles would take her 28 minutes 3 miles would take her 42 minutes and finally if she walked 4 miles it would take her 56 minutes.

14 + 14 + 14 + 14 = 56

14 x 4 = 56

3 0

3 years ago

Find the error and explain what there is incorrectly. Then, solve the problem correctly.

frez [133]

The problem is that 7^2 is 7*7, and the same for 8^2. The right answer is the square root of 15, or 3.87

3 0

3 years ago

Read 2 more answers

Find all points on the x-axis that are 14 units from the point (6,-7) All points on the x-axis that are 14 units from the point

Maksim231197 [3]

Answer: $(6+7\sqrt{3},0)\text{ and }(6-7\sqrt{3},0)$ are the required points.

or (18.124,0) and ( -6.124,0) are the required points.

Step-by-step explanation:

Let (x,0) be the point on x -axis that are 14 units from the point (6,-7) .

Then by distance formula , we have

$\sqrt{(x-6)^2+(0-(-7))^2}=14\ \ \ [\ \because distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}]$

Taking square on both the sides , we get

$(x-6)^2+7^2=14^2\\\\\Rightarrow\ x^2+6^2-2(6)x+49=196\\\\\Rightarrow\ x^2+36-12x=147\\\\\Rightarrow\ x^2-12x=111\\\\\Rightarrow\ x^2-12x-111=0$

Using quadratic formula : $x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\dfrac{12\pm\sqrt{(-12)^2-4(1)(-111)}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{144+444}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{588}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{2^2\times7^2\times3}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm14\sqrt{3}}{2}\\\\\Rightarrow\ x=6\pm7\sqrt{3}$