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4 years ago

10

Which of the following is equivalent to the polynomial below

1 answer:

natta225 [31]4 years ago

8 0

For this case what you must do is find the roots of the corresponding polynomial by means of a factorization.
We have then:
x ^ 2-10x + 61
(x- (5 + 6i)) (x- (5-6i))
Checking:
(x- (5 + 6i)) (x- (5-6i))
x ^ 2 - x * (5-6i) - (5 + 6i) x + (5 + 6i) * (5-6i)
x ^ 2 - 5x + 6ix - 5x- 6ix + 25 - 30i + 30i + 36
x ^ 2 -10x + 61
Answer:
(x- (5 + 6i)) (x- (5-6i))

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A city doubles its size every 64 year. If the population is currently 225,000, what will the population be in 128 years?

Rudiy27

Answer:

=900000

Step-by-step explanation:

the current ppl=225000

after 64 years=225000×2=450000

in the next 64 yrs(128 yrs later)=450000×2=900000

3 0

3 years ago

I know you want to answer this question.

Alik [6]

Answer:

D. x = 3

Step-by-step explanation:

$\frac{1}{2} ^{x-4}$ - 3 = $4^{x-3}$ - 2

First, convert $4^{x-3}$ to base 2:

$4^{x-3}$ = $(2^{2})^{x-3}$

$\frac{1}{2} ^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Next, convert $\frac{1}{2} ^{x-4}$ to base 2:

$\frac{1}{2} ^{x-4}$ = $(2^{-1})^{x-4}$

$(2^{-1})^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{-1})^{x-4}$ = $2^{-1*(x-4)}$

$2^{-1*(x-4)}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{2})^{x-3}$ = $2^{2(x-3)}$

$2^{-1*(x-4)}$ - 3 = $2^{2(x-3)}$ - 2

Apply exponent rule: $a^{b+c}$ = $a^{b}$ $a^{c}$ :

$2^{-1(x-4)}$ = $2^{-1x}$ * $2^{4}$ , $2^{2(x-3)}$ = $2^{2x}$ * $2^{-6}$

$2^{-1 * x}$ * $2^{4}$ - 3 = $2^{2x}$ * $2^{-6}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$2^{-1x}$ = $(2^{x})^{-1}$ , $2^{2x}$ = $(2^{x})^{2}$

$(2^{x})^{-1}$ * $2^{4}$ - 3 = $(2^{x})^{2}$ * $2^{-6}$ - 2

Rewrite the equation with $2^{x} = u$ :

$(u)^{-1}$ * $2^{4}$ - 3 = $(u)^{2}$ * $2^{-6}$ - 2

Solve $u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2:

$u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2

Refine:

$\frac{16}{u}$ - 3 = $\frac{1}{64}$ $u^{2}$ - 2

Add 3 to both sides:

$\frac{16}{u}$ - 3 + 3 = $\frac{1}{64}$ $u^{2}$ - 2 + 3

Simplify:

$\frac{16}{u}$ = $\frac{1}{64}$ $u^{2}$ + 1

Multiply by the Least Common Multiplier (64u):

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify:

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify $\frac{16}{u}$ * 64u:

1024

Simplify $\frac{1}{64}$ $u^{2}$ * 64u:

$u^{3}$

Substitute:

1024 = $u^{3}$ + 64u

Solve for u:

u = 8

Substitute back u = $2^{x}$ :

8 = $2^{x}$

Solve for x:

x = 3

4 0

3 years ago

What is an equation in point-slope form of the line that passes through the point (4,4) and has a slope of -5?

Nastasia [14]

(y - 4) = -5 (x - 4)

3 0

3 years ago

Write 7,380,000,000 in scientific notation.

uysha [10]

7.380 times 10 to the 9th power (or 7.38 times 10 to the 9th power)

5 0

3 years ago

Read 2 more answers

The above is a a a a a a a a a a a a a a a a a a a

Reptile [31]

X f πxf

-1 2 -2

3 1 3

-1 -2 2

0 -3 0

total =3

mean (π)=πxf ÷n

= 3÷4

= 0.75 these is not answer I thank so

3 0

3 years ago