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3 years ago

Help with this? will give points

Mathematics

2 answers:

SVEN [57.7K]3 years ago

8 0

Answer:

A. ∛5s²t / st

Step-by-step explanation:

∛5 / ∛st² = (∛5 x (∛s²t)) / ((∛st²) x (∛s²t))

=∛5s²t / ∛s³t³ = ∛5s²t / st

mestny [16]3 years ago

5 0

Answer: I think the best answer is C

Step-by-step explanation:

You might be interested in

Farmer Theresa's Produce Stand sells 27.5 lbs. bags of mixed nuts that contain 44% peanuts. To make her product she combines Bra

masya89 [10]

Answer:

Theresa needs 14.3 pounds of Brand A mixed nuts and 13.2 pounds of Brand B mixed nuts.

Step-by-step explanation:

Let A represent the brand A mixed nuts and B represent Brand B mixed nuts.

We have been given that farmer Theresa's Produce Stand sells 27.5 lbs. bags. We can represent this information in an equation as:

$A+B=27.5...(1)$

We are also told that to make her product she combines Brand A mixed nuts which contain 20% peanuts and Brand B mixed nuts which contain 70% peanuts.

We can represent this information in an expression as:

$0.20A+0.70B$

Since the stand sells 27.5 lbs. bags of mixed nuts that contain 44% peanuts. We can represent this information in an equation as:

$0.20A+0.70B=0.44(27.5)...(2)$

Upon substituting equation (1) in equation (2), we will get:

$0.20(27.5-B)+0.70B=0.44(27.5)$

$5.50-0.20B+0.70B=12.10$

$5.50+0.50B=12.10$

$5.50-5.50+0.50B=12.10-5.50$

$0.50B=6.6$

$\frac{0.50B}{0.50}=\frac{6.6}{0.50}$

$B=13.2$

Therefore, Theresa needs 13.2 pounds of Brand A mixed nuts.

To find amount of Brand B mixed nuts, we will substitute $B=13.2$ in equation (1) as:

$A+13.2=27.5$

$A+13.2-13.2=27.5-13.2$

$A=14.3$

Therefore, Theresa needs 14.3 pounds of Brand B mixed nuts.

5 0

4 years ago

Mata exercises 30 minutes each day Greg exercises for 10 minutes each day how many more minutes that's Greg exercise in a month

barxatty [35]

Answer:

620 minutes

Step-by-step explanation

In one day,Mata exercise 20minutes more than Greg

31 days so we have 20 *31=620

6 0

3 years ago

Brian pays £475.29 a year on his car insurance. The insurance company reduces the price by 2.1%. How much does the insurance cos

Ymorist [56]

Answer:

$\£465.31$

Step-by-step explanation:

we know that

The insurance company reduces the price by 2.1%

Remember that

The actual cost of £475.29 a year represent the 100%

$100\%-2.1\%=97.9\%=97.9/100=0.979$

To find out the new insurance cost, multiply the original cost by the factor 0.979

$\£475.29(0.979)=\£465.31$

6 0

3 years ago

Read 2 more answers

Find the present balance.

Triss [41]

<h3>Credited balance:-</h3>

$\\ \rm\longmapsto 115.90+115.90+345.85$

$\\ \rm\longmapsto 231.80+345.85$

$\\ \rm\longmapsto 577.65$

<h3>Debited amount:-</h3>

$\\ \rm\longmapsto 25.85+2.00$

$\\ \rm\longmapsto 27.85$

<h3>Checked amount:-</h3>

$\\ \rm\longmapsto 19.45+21.02+95.98$

$\\ \rm\longmapsto 117+19.45$

$\\ \rm\longmapsto 136.45$

<h3>Total change in balance</h3>

$\\ \rm\longmapsto 577.65-(27.85+136.45)$

$\\ \rm\longmapsto 577.65-191.3$

$\\ \rm\longmapsto 386.35$

Now

<h3>Current balance</h3>

$\\ \rm\longmapsto 386.35+271.31$

$\\ \rm\longmapsto\$ 657.66$

8 0

3 years ago

Car X weighs 136 pounds more than car Z. Car Y weighs 117 pounds more than car Z. The total weight of all three cars is 9439 pou

Aleksandr [31]

Let x, y and z denote the weighs of car X, car Y and car Z, respectively.

We know that car X weighs 136 more than car Z, this can be express by the equation:

$x=z+136$

We also know that Y weighs 117 pounds more than car Z, this can be express as:

$y=z+117$

Finally, we know that the total weight of all the cars is 9439, then we have:

$x+y+z=9439$

Hence, we have the system of the equations:

$\begin{gathered} x=z+136 \\ y=z+117 \\ z+y+z=9439 \end{gathered}$

To solve the system we can plug the values of x and y, given in the first two equations, in the last equation; then we have:

$\begin{gathered} z+136+z+117+z=9439 \\ 3z=9439-136-117 \\ 3z=9186 \\ z=\frac{9186}{3} \\ z=3062 \end{gathered}$

Now that we have the value of z we plug it in the first two equations to find x and y:

$\begin{gathered} x=3062+136=3198 \\ y=3062+117=3179 \end{gathered}$

Therefore, car X weighs 3198 pound, car Y weighs 3179 pounds and car Z weighs 3062 pounds.

4 0

1 year ago