Hi,
The two numbers should be 12 and 30. 12=2x2x3 while 30=2x3x5.
Their HCF is 2x3=6 and their LCM is 2x3x2x5. Because of their HFC, we know that they are both multiple of 6. Also, the question says they both are GREATER than 6, so they can’t be 6 but are 6 times “something”. Thanks to the LCM, we know that “something” is equal to 2 for the first number and to 5 for the second one, the numbers hence being 12 and 30.
I hope this helps. If I was not clear enough or if you’d like further explanation please let me know. Also, English is not my first language, so I’m sorry for any mistakes.
Answer:
For the sum of the digits of Michelle’s father to drop to 1/3 of its’ former value, the second digit must go from 9 to 0, in one year.
Thus, if he is 39 this year, the sum of the digits of his age will be 12. Next year, when the sum of the digits would be 4+0, or 4, then the digits of his age would be 1/3rd of their former value.
Therefore, he is 39, and will be 40 next year
Step-by-step explanation:
Answer:
c) (8^6) / 8 = 32768
d) (7^8) / (7^6) = 49
Step-by-step explanation:
Answer:
separate the x from the numbers it will make the equation easier
16. 4 (9*4=36)
17. 6 (6*11=66)
18. 8 (10*8=80)
19. 9 (9*5=45)
20. 48 (4*12=48)
21. 13 (13*2=26)