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patriot [66]
3 years ago
13

$206.88 with a 5.75% sales tax

Mathematics
1 answer:
7nadin3 [17]3 years ago
5 0
206.88*1.0575= $ <span>218.7756</span>
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Solve the equation <br> pleasse someone please help will give brainliest pleeeasse ​
NISA [10]

Answer:

45 it is 45 45 um yea I ben did thiss

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2 years ago
Jenny has saved $3,800 over the last 12 months. She saved either $250 or $350 a month. During the 12 month period, how many time
kari74 [83]
 5 months for it 5 times 250= 1250 
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3 years ago
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twice the sum of a number and 6 is equal to 3 times the difference of the number and 8. Find the number
Serhud [2]

In order to solve this problem, we must solve an equation.

First, we need to define our unknown.

Let's call our number "n".


So, the sum of the number and 6 is the same as saying n+6

Then we need to multiply it by 2 (since it's twice the sum)

2(n+6)

This whole thing is equal to three times of the difference of the number and 8

n-8 is equal to the difference between the number and 8, then we need to multiply it by three.

3(n-8)

now, we set both sides equal and solve

2(n+6)=3(n-8)\\2n+12=3(n-8)\\2n+12=3n-24\\12=n-24\\36=n

The number is 36

5 0
3 years ago
Quadrilateral ABCD is a rhombus. suppose measure of angle A decreases. Which of the following changes woukd also need to happen
Harlamova29_29 [7]
Assuming the side lengths did not change, ...

Angle C would need to decrease by the same amount.
Angles B and D would each need to increase by the amount angle A decreased.
6 0
3 years ago
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Find the size of each of two samples (assume that they are of equal size) needed to estimate the difference between the proporti
hodyreva [135]

Answer:

The sample size n = 4225

Step-by-step explanation:

We will use maximum error formula = \frac{z_{a} S.D}{\sqrt{n} }

but we will find sample size "n"

\sqrt{n}  = \frac{z_{a} S.D}{maximum error}

Squaring on both sides , we get

n  = (\frac{z_{a} S.D}{maximum error})^2

Given 99% confidence interval (z value) = 2.56

given maximum error = 0.02

n  = (\frac{z_{a} p(1-p)}{maximum error})^2

n≤ (\frac{2.56X\frac{1}{2} }{0.02}) ^{2}    ( here S.D = p(1-p) ≤ 1/2

on simplification , we get n = 4225

<u>Conclusion</u>:

The sample size of two samples is  n = 4225

<u>verification</u>:-

We will use maximum error formula = \frac{z_{a} S.D}{\sqrt{n} } = \frac{2.56 1/2}{\ \sqrt{4225} }  = 0.0196

substitute all values and simplify we get maximum error is 0.02

4 0
3 years ago
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