Step 1: Find the area of the bases (triangles)
A = 1/2 * base * height
A = 1/2 * 16 * 6
A = 48
48 + 48 = 96
Area of the triangles = 96 cm^2
Step 2: Find the area of the sides (rectangles)
A = base * height
A1 = 16 * 12
A1 = 192
A2 = 10 * 12
A2 = 120
120 + 120 = 240
240 + 192 = 432 cm^2
Step 2: Add the areas together
96 + 432
528 cm^2
Hope this helps!! :)
Step-by-step explanation:
(x^4)^3=(x^3)^4 , true
=> x^(4×3) = x^(3×4) = x^12
13^4 x 13^7= (13^4)^7, false
13^(4+7) = 13^11
(13^4)^7 = 13^(4×7) = 13^28
y^5 x y^0/y^3=(y^2)^1 , true
y^5 x y^0/y^3 = y^(5+0-3) = y^2
(y^2)^1 = y^(2×1) = y^2
q^0 x q^5/q^2=(q^3)^2/q^3, true
q^0 x q^5/q^2= q^(0+5-2)= q^3
(q^3)^2/q^3 = q^(3×2-3) = q^3
Ask your teacher that’s all you have to do.
