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Gennadij [26K]
3 years ago
11

(x^4)^3=(x^3)^4 true or false

Mathematics
2 answers:
aksik [14]3 years ago
8 0

Answer:

1) { ({x}^{4})}^{3}  =  { ({x}^{3} )}^{4}  \\ power \: multiply \\  {x}^{12}  =  {x}^{12}  =  > true \\ 2) {13}^{4}  \times  {13}^{7}  =   \\ power \: add \\   {13}^{11} not \:  =   { {13}^{4} }^{7}  \\  =  > false \\ 3)  \frac{ {y}^{5}  {y}^{0} }{ {y}^{3} }  =  { {y}^{2} }^{1}  \\   {y}^{2}  =  {y}^{2}   \\  =  > true \\ 4) \frac{ {q}^{0}{q}^{5}  }{ {q}^{2} }  =  \frac{ { {q}^{3} }^{2} }{ {q}^{3} }  \\ {q}^{3}  =  {q}^{3}  \\  =  > true \\ thank \: you

telo118 [61]3 years ago
6 0

Step-by-step explanation:

(x^4)^3=(x^3)^4 , true

=> x^(4×3) = x^(3×4) = x^12

13^4 x 13^7= (13^4)^7, false

13^(4+7) = 13^11

(13^4)^7 = 13^(4×7) = 13^28

y^5 x y^0/y^3=(y^2)^1 , true

y^5 x y^0/y^3 = y^(5+0-3) = y^2

(y^2)^1 = y^(2×1) = y^2

q^0 x q^5/q^2=(q^3)^2/q^3, true

q^0 x q^5/q^2= q^(0+5-2)= q^3

(q^3)^2/q^3 = q^(3×2-3) = q^3

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Step-by-step explanation:

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8 0
3 years ago
Write the recursive rule and the iterative rule for the following sequence: 10, 6, 2, -2, -6
barxatty [35]
The recursive rule is
a_n=a_{n-1}+(-4). 
The iterative rule is
a_n=14-4n

The recursive rule is given by the formula 
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The iterative rule begins with the formula
a_n=a_1+d(n-1), where a₁ is the first term and d is the common difference.  Our first term is 10 and our common difference is -4:
a_n=10+(-4)(n-1)
\\\text{Using the Distributive Property,}
\\
\\a_n=10+(-4*n)+(-4*-1)
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\\a_n=10-4n+4
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\\\text{Combining like terms,}
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7 0
3 years ago
Which unit would be most appropriate to measure the
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5 0
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6 0
3 years ago
For all x, 5-3(x-4)=
velikii [3]

Simplify

Let's simplify step-by-step.

x(5)−3(x−4)

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=5x+−3x+12

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Answer:

=2x+12

8 0
3 years ago
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