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Gennadij [26K]
2 years ago
11

(x^4)^3=(x^3)^4 true or false

Mathematics
2 answers:
aksik [14]2 years ago
8 0

Answer:

1) { ({x}^{4})}^{3}  =  { ({x}^{3} )}^{4}  \\ power \: multiply \\  {x}^{12}  =  {x}^{12}  =  > true \\ 2) {13}^{4}  \times  {13}^{7}  =   \\ power \: add \\   {13}^{11} not \:  =   { {13}^{4} }^{7}  \\  =  > false \\ 3)  \frac{ {y}^{5}  {y}^{0} }{ {y}^{3} }  =  { {y}^{2} }^{1}  \\   {y}^{2}  =  {y}^{2}   \\  =  > true \\ 4) \frac{ {q}^{0}{q}^{5}  }{ {q}^{2} }  =  \frac{ { {q}^{3} }^{2} }{ {q}^{3} }  \\ {q}^{3}  =  {q}^{3}  \\  =  > true \\ thank \: you

telo118 [61]2 years ago
6 0

Step-by-step explanation:

(x^4)^3=(x^3)^4 , true

=> x^(4×3) = x^(3×4) = x^12

13^4 x 13^7= (13^4)^7, false

13^(4+7) = 13^11

(13^4)^7 = 13^(4×7) = 13^28

y^5 x y^0/y^3=(y^2)^1 , true

y^5 x y^0/y^3 = y^(5+0-3) = y^2

(y^2)^1 = y^(2×1) = y^2

q^0 x q^5/q^2=(q^3)^2/q^3, true

q^0 x q^5/q^2= q^(0+5-2)= q^3

(q^3)^2/q^3 = q^(3×2-3) = q^3

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Answer:

x can be cancelled

Step-by-step explanation:

we are given

\frac{4x^3-10x^2+6x}{2x^3+x^2-3x}

Firstly, we will factor numerator and denominator

and then we can factor it

4x^3-10x^2+6x=2x(2x^2-5x+3)

4x^3-10x^2+6x=2x(2x+1)(x-3)

now, we can factor denominator

2x^3+x^2-3x=x(2x^2+x-3)

2x^3+x^2-3x=x(x-1)(2x+3)

now, we can replace it

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we can see that

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