Answer:
a) P(X<50)=0.9827
b) P(X>47)=0.4321
c) P(-1.5<z<1.5)=0.8664
Step-by-step explanation:
We will calculate the probability based on a random sample of one moped out of the population, normally distributed with mean 46.7 and standard deviation 1.75.
a) This means we have to calculate P(x<50).
We will calculate the z-score and then calculate the probability accordign to the standard normal distribution:

b) We have to calculatee P(x>47).
We will calculate the z-score and then calculate the probability accordign to the standard normal distribution:

c) If the value differs 1.5 standard deviations from the mean value, we have a z-score of z=1.5

So the probability that maximum speed differs from the mean value by at most 1.5 standard deviations is P(-1.5<z<1.5):

The number of more miles he needs to run to complete the race is 19 miles.
<h3 /><h3>How to find distance in miles?</h3>
He has run 7 miles from point a to point b of a race.
The entire race from point a to point c is 26 miles.
Therefore, the number of more miles he needs to run to complete the race is as follows:
let
x = the more miles he needs to run
Hence,
x = 26 - 7
x = 19 miles
Therefore, he needs to run 19 more miles to complete the race.
learn more on distance(miles) here: brainly.com/question/9950097
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Answer:
(x , y) ----> (-x , y)
Step-by-step explanation:
(x , y) ----> (-x , y)
Example for 1. :
(-4,2) ---> (4,2)
Convert them to comparable thingummys
convert to fraction
percent means parts out of 100
30%=30/100=3/10
3/10 vvs 1/3
make bottom number 30
3/10 times 3/3=9/30
1/3 times 10/10=10/30
10/30>9/30
1/3 is bigger
Answer:
perimeter of the shaded region = 88 +44+28 =160 cm
Step-by-step explanation:
perimeter of shaded region = length AO + arc OB + arc AB
length AO = radius of bigger circle
radius of bigger circle = OX + OB = 2×radius of smaller circle = 2×14 cm = 28 cm
therefore AO = 28 cm
length of arc oB= half of circumference of smaller circle =
×14 = 44 cm
length of arc ab = half of circumference of bigger circle =
×28 =
×28= 88
therefore perimeter of the shaded region = 88 +44+28 =160 cm
area of the shaded region = half of area of bigger circle - half of area of smaller circle
=
=
solving we gen area of shaded region = 924