Answer:
C : does not have statistical significance
Step-by-step explanation:
Because there is a 15% chance of getting that many girls by chance, the method - does not have statistical significance.
By this method, the percentage of girls =
or 51.15%
This type of method does not have practical significance.
You are told to choose the choices equal to T(8). T(8) means that you need to find the possible ways to write the y-value when n = 8, since 8 is being substituted in for "n."
1) First, plug in n = 8 into the equation you're given, <span>T(n) = 4n - 5:
T(8) = 4(8) - 5
T(8) = 32 - 5
T(8) = 27
That is answer choice C, making choice C correct. You can eliminate choice B, since 27 </span>≠ 37.
2) Check answer choice A. Is T(5) + T(3) = 27? T(5) means you need to plug in 5 for n. T(3) means you need to plug in 3 for n.
T(5) + T(3)
= [4(5) - 5] + [4(3) - 5]
= [20-5] + [12-5]
= 15 + 7
= 22
Since 22 ≠ 27, you can eliminate choice A.
3) Check answer choice D. Is T(7) + 4 = 27? T(7) means you need to plug in 7 for n.
T(7) + 4
= [<span>4(7) - 5] + 4
</span>= [28 - 5] + 4
= 23 + 4
= 27
Since 27 = 27, answer choice D is also correct!
--------
Answer: Choice C (27) and Choice D (T(7) + 4)
Answer:
The 68% confidence interval for the population proportion of college seniors who plan to attend graduate school is (0.16, 0.24).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
A recent survey showed that among 100 randomly selected college seniors, 20 plan to attend graduate school and 80 do not.
This means that 
68% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 68% confidence interval for the population proportion of college seniors who plan to attend graduate school is (0.16, 0.24).
The closest is D . But it should be + x^2 not - x^2