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3 years ago

Two similar triangles are congruent always, sometimes, or never?

Mathematics

2 answers:

Talja [164]3 years ago

5 0

Answer:

I think the answer is: sometimes

zimovet [89]3 years ago

5 0

congruency means, exact twins, completely exact.

similarity means, they must look the same only, one can be larger or smaller than the other, the angles must be the same, but the lengths can be longer or shorter and that's ok.

if two figures are congruent, they are also similar, but if one is larger than the other, they're still similar, though not congruent anymore.

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Which phrase in paragraph 3 of "The pit and the Pendulum" most strongly contributes to a mood of trade

BaLLatris [955]

Answer:

"and motion, and touch—a tingling

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3 years ago

If an interior angle of a regular polygon measures 140°, how many sides does the polygon have?

Delicious77 [7]

Answer:

9 sides!

Step-by-step explanation:

Nonagon has it's each interior angle measure as 140 degrees.

Polygon with 9 sides!

8 0

4 years ago

Please help on this one?

Readme [11.4K]

A i think it could be wrong im only in middle school

3 0

3 years ago

Read 2 more answers

I WILL AWARD BRAINLIEST!! PLEASE HELP!!

Veseljchak [2.6K]

Answer:

$1)\\\large\boxed{x=\dfrac{a+c}{b},\ if\ b\neq0}\\\\2)\\\boxed{if\ a=\dfrac{63b}{23}\ then\ x\ is\ any\ real \ number}\\\\\boxed{if\ a\neq\dfrac{63b}{23}\ then\ x\ not\ exist\ (no\ solution)}$

Step-by-step explanation:

$1)\\a-(a+b)x=(b-a)x-(c+bx)\qquad\text{use the distributive property}\ a(b+c)=ab+ac\\\\a-ax-bx=bx-ax-c-bx\qquad\text{cancel}\ bx\ \text{on the right side}\\\\a-ax-bx=-ax-c\qquad\text{add}\ ax\ \text{to both sides}\\\\a-bx=-c\qquad\text{subtract}\ a\ \text{from both sides}\\\\-bx=-a-c\qquad\text{divide both sides by}\ -b\neq0\\\\x=\dfrac{-a-c}{-b}\\\\x=\dfrac{a+c}{b}$

$2)\\2(3x-5a)+9(2a-7b)+3(5a-2x)=0\\\\\text{use the distributive property}\ a(b+c)=ab+ac\\\\(2)(3x)+(2)(-5a)+(9)(2a)+(9)(-7b)+(3)(5a)+(3)(-2x)=0\\\\6x-10a+18a-63b+15a-6x=0\qquad\text{combine like terms}\\\\(6x-6x)+(-10a+18a+15a)-63b=0\\\\23a-63b=0\qquad\text{add}\ 63b\ \text{to both sides}\\\\23a=63b\qquad\text{divide both sides by 23}\\\\a=\dfrac{63b}{23}\\\\if\ a=\dfrac{63b}{23}\ then\ x\ is\ any\ real \ number\\\\if\ a\neq\dfrac{63b}{23}\ then\ x\ not\ exist\ (no\ solution)$

3 0

4 years ago

Ok.......................................................

quester [9]

Answer:

Hello there do you need help, if so what is he problem:)

Step-by-step explanation:

7 0

3 years ago