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3 years ago

8

While participating in a blood drive at school, Keona learns that blood has a density of 1.06 g/mL. She donates one pint of bloo

d, which is equal to 473.176 mL.
What is the mass of the blood Keona donates, to the nearest hundredth of a gram?
The mass of the blood Keona donates is ____ g.

2 answers:

Alla [95]3 years ago

6 0

Answer:501.57g

Step-by-step explanation:

Novosadov [1.4K]3 years ago

5 0

Answer:

501.57g

Step-by-step explanation:

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Problem Situation: Ben buys a table for $240. He also buys 6 chairs that all cost the same amount. His total cost is $720. What

butalik [34]

Answer:

80 Dollars per chair

Step-by-step explanation:

Step One:

Subtract 720 by (-) 240

this should give you, 480

Step Two:

Divide 480 by 6

Which gives you your answer 80

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2 years ago

There were 442 students at Deerlake Middle School who voted on a theme for the spring carnival. Those who voted represent 76% of

never [62]

Answer:

Option C is correct.

Step-by-step explanation:

Number of students of Deerlake middle school that voted = 442

Percentage of student that voted = 76%

Let x be the total number of student.

According to the Question,

$\frac{76}{100}\times x=442$

$x=442\times\frac{100}{76}$

$x=582$

Therefore, Option C is correct.

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3 years ago

Standard Error from a Formula and a Bootstrap Distribution Sample A has a count of 30 successes with and Sample B has a count of

tia_tia [17]

Answer:

Using a formula, the standard error is: 0.052

Using bootstrap, the standard error is: 0.050

Comparison:

The calculated standard error using the formula is greater than the standard error using bootstrap

Step-by-step explanation:

Given

Sample A Sample B

$x_A = 30$ $x_B = 50$

$n_A = 100$ $n_B =250$

Solving (a): Standard error using formula

First, calculate the proportion of A

$p_A = \frac{x_A}{n_A}$

$p_A = \frac{30}{100}$

$p_A = 0.30$

The proportion of B

$p_B = \frac{x_B}{n_B}$

$p_B = \frac{50}{250}$

$p_B = 0.20$

The standard error is:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * (1 - 0.30)}{100} + \frac{0.20* (1 - 0.20)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * 0.70}{100} + \frac{0.20* 0.80}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.21}{100} + \frac{0.16}{250}}$

$SE_{p_A-p_B} = \sqrt{0.0021+ 0.00064}$

$SE_{p_A-p_B} = \sqrt{0.00274}$

$SE_{p_A-p_B} = 0.052$

Solving (a): Standard error using bootstrapping.

Following the below steps.

Open Statkey
Under Randomization Hypothesis Tests, select Test for Difference in Proportions
Click on Edit data, enter the appropriate data
Click on ok to generate samples
Click on Generate 1000 samples ---- <em>see attachment for the generated data</em>

From the randomization sample, we have:

Sample A Sample B

$x_A = 23$ $x_B = 57$

$n_A = 100$ $n_B =250$

$p_A = 0.230$ $p_A = 0.228$

So, we have:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.23 * (1 - 0.23)}{100} + \frac{0.228* (1 - 0.228)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.1771}{100} + \frac{0.176016}{250}}$

$SE_{p_A-p_B} = \sqrt{0.001771 + 0.000704064}$

$SE_{p_A-p_B} = \sqrt{0.002475064}$

$SE_{p_A-p_B} = 0.050$

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2 years ago

Write the equation of the line in slope-intercept form given the graph below.

pishuonlain [190]

Answer:

y=-2/3x-1

Step-by-step explanation:

4 0

2 years ago

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kipiarov [429]

$\frac{5x^{5}-3x^{3}+2x^{2}-x}{x+2}=5x^{4}-10x^{3}+17x^{2}-32x+63- \frac{126}{x+2}$

The coefficient of the x term is -32.

7 0

3 years ago