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MA_775_DIABLO [31]
3 years ago
14

Write a equation for the new circle obtained by translating the circle:

Mathematics
1 answer:
AysviL [449]3 years ago
7 0

Answer:

bruvulmuffin

Step-by-step explanation:

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43.78 = forty three and seventy eight hundredths.
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What is the value of sin-1(1)? negative startfraction pi over 2 endfraction 0 startfraction pi over 2 endfraction π
mariarad [96]

The value of sin-1(1) is negative startfraction pi over 2 endfraction, startfraction -pi over 2 endfraction.

<h3>What is the value of sin (π/2)?</h3>

The value of sin (π/2) is equal to the number 1. The value of the sin-1(1) has to be find out.

Suppose the value of this function is <em>x</em>. Thus,

x=\sin^{-1}(1)

Solve it further,

\sin(x)=(1)              ......1

The value of sin (π/2) and -sin (-π/2) is equal to 1 such that,

\sin\dfrac{\pi}{2}=-\sin\left(-\dfrac{\pi}{2}\right)=1

Put this value in the equation 1,

\sin(x)=\sin\left(\dfrac{\pi}{2}\right)=-\sin\left(-\dfrac{\pi}{2}\right)

Thus, the range will be,

\left(\dfrac{\pi}{2},-\dfrac{\pi}{2}\right)

Thus, the value of sin-1(1) is negative startfraction pi over 2 endfraction, startfraction -pi over 2 endfraction.

Learn more about the sine values here;

brainly.com/question/10711389

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3 years ago
What is the second law of exponents
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Subtract 1 2 12 12 from both sides of the equation + 1 2 = 2 1 + 1 2 − 1 2 = 2 1 − 1 2 2 Simplify Solution = 9

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