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3 years ago

Does anyone know how to do this csc x ( sin x + cos x) = 1 + cot x

Mathematics

1 answer:

Dima020 [189]3 years ago

8 0

9514 1404 393

Explanation:

Use the identities ...

csc(x) = 1/sin(x)

cot(x) = cos(x)/sin(x)

$\csc(x)(\sin(x)+\cos(x))=1+\cot(x)\\\\\dfrac{1}{\sin(x)}(\sin(x)+\cos(x))=1+\cot(x)\\\\\dfrac{\sin(x)}{\sin(x)}+\dfrac{\cos(x)}{\sin(x)}=1+\cot(x)\\\\1+\cot(x)=1+\cot(x)$

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bearhunter [10]

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The correct answer is: "The y's because the coefficients are the same."

Further explanation:

we always try to eliminate the variable from the system of equations which involves lesser calculations and complexity.

Assuming that Given equations are:

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Hence,

The correct answer is: "The y's because the coefficients are the same."

Keywords: Linear equations, variables

Learn more about linear equations at:

#LearnwithBrainly

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4 years ago

Does anyone know how to do this csc x ( sin x + cos x) = 1 + cot x ​

Does anyone know how to do this csc x ( sin x + cos x) = 1 + cot x