1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
baherus [9]
3 years ago
10

What is 247,039 rounded to the nearest thousand

Mathematics
1 answer:
DerKrebs [107]3 years ago
6 0
<span><u><em>Answer:</em></u>
247,000

<u><em>Explanation:</em></u>
To round a number to the nearest thousand, we check the digit in the <u>hundreds position</u>:
1- If the digit is <u>less than 5</u>, then we round down. This means that we simply convert all digits after the thousands to zero and that's it
2- If the digit is <u>equal to or more than 5</u>, then we round up. This means that we add one to the thousands digit and then convert all digits after the thousands to zero.

In the given number 247039, the number in the hundreds position is 0. This means that we will <u>round down
</u>
Therefore, 246039 rounded to the nearest thousand would simply give 247000

Hope this helps :)</span>
You might be interested in
Is -77 a rational or irrational number?​
Butoxors [25]

It’s a rational number.

Hope this helps!

7 0
3 years ago
Read 2 more answers
I NEED HELP ON THESE ASAPPPPPP
Lana71 [14]

Answer:

1. (-3,-11),(-2,-8),(-1,-5),(0,-2)(1,1)(2,4) (3,7)

2 (-3,5),(-2,0),(-1,-3), (0,-4),(1,-3),(2,0),(3,5)

3 0
2 years ago
If x&lt;0 and y&gt;0, determine the sign of the real number x-y/xy ...?
Ludmilka [50]
If x<0 and y>0, then the sign of the real number x-y/xy would be positive. <span>If x is negative and y is positive then x-y is negative and xy is negative. A negative number  divided by another negative number would be positive. Hope this answers the question.</span>
4 0
3 years ago
write the equation in standard form for the hyperbola with vertices ( – 12,0) and (12,0), and foci ( – 13,0) and (13,0).
Mashcka [7]

Standard form for the hyperbola with vertices ( – 12,0) and (12,0), and foci ( – 13,0) and (13,0) is \frac{x^{2} }{144}-\frac{y^{2} }{25}=1

Hyperbola is a plane curve generated by a point so moving that the difference of the distances from two fixed points is a constant.

Given,

The Vertices of the hyperbola =  (-12,0) and (12,0)

Foci = (-13,0) and (13,0)

a=12

ac=13

c=\frac{13}{12}

We know,

c=\sqrt{1+\frac{b^{2} }{a^{2} } }

c^{2}=1+\frac{b^{2} }{a^{2} }  \\(\frac{13}{12} )^{2}=1+\frac{b^{2} }{144}  \\\frac{169}{144}=1+ \frac{b^{2} }{144} \\\frac{b^{2} }{144} =\frac{25}{144}\\ b^{2}=25

The equation of the hyperbola is

\frac{x^{2} }{a^{2} }-\frac{y^{2} }{b^{2} }=1\\  \frac{x^{2} }{144 }-\frac{y^{2} }{25 }=1

Hence, the standard form for the hyperbola with vertices ( – 12,0) and (12,0), and foci ( – 13,0) and (13,0) is \frac{x^{2} }{144}-\frac{y^{2} }{25}=1

Learn more about hyperbola here

brainly.com/question/7098764

#SPJ4

4 0
2 years ago
Please help me on this!
Mumz [18]

Answer:

C. -0.97

Step-by-step explanation:

that is the approximate correlation coefficient

6 0
2 years ago
Other questions:
  • In ΔTUV, t = 6.6 inches, ∠U=71° and ∠V=36°. Find the length of u, to the nearest 10th of an inch.
    7·1 answer
  • URGENT PLEASE HELP
    15·1 answer
  • 45 + 5 = what i need so HELP
    6·2 answers
  • This spinner is spun 36 times. The spinner landed on A 6 times, on B 21 times, and on C 9 times. Compute the empirical probabili
    10·1 answer
  • I need help i honestly dont get this​
    10·1 answer
  • Compare the rates to find which is the better value.<br> ​$60 for 100 flyers or ​$95 for 250 flyers
    7·1 answer
  • 1.5.2. You have a six-sided die that you roll once. Let Ri denote the event that the roll is i. Let Gj denote the event that the
    15·1 answer
  • I need help can someone tell me how to do this plz
    14·2 answers
  • Price of article = $315.50
    9·1 answer
  • Which equation represents the relationship between x and y shown in the table?
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!