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3 years ago

Multiply 5( 4n -5) tell me how

Mathematics

1 answer:

rewona [7]3 years ago

8 0

Distribute

5 × 4n + 5 × -5

Simplify 5 × 4n to 20n

20n + 5 × -5

Simplify 5 × -5 to -25

20n - 25

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1/6(a+12)= -4 please help because I don’t understand this

iogann1982 [59]

Answer:

a=-36

Step-by-step explanation:

1/6(a+12)=-4

1) Distribute 1/6 to a and 12:

1/6a+2=-4

2) Subtract 2 from both sides:

1/6a=-6

3) Multiply both sides by the reciprocal of 1/6: (6/1)

a=-36

Let me know if you have any confusion on how I reached the solution :)

3 0

3 years ago

Can someone please help me!

ANEK [815]

Answer:

<h2>Answer :- </h2>

Option D :- (180 - 2x)°

<h3>Hope it helped :)</h3>

3 0

2 years ago

24 and 25 thanksssssss

german

24:D
25:C
you’re welcome

6 0

3 years ago

V=4/3pir^3 solve for r

Ne4ueva [31]

$V= \frac{4}{3 \pi r^3} \\V 3\pi r^3=4 \\ r^3= \frac{4}{3 \piV } \\ r= \sqrt[3]{\frac{4}{3 \pi V}}$

3 0

3 years ago

Subtract rational expression. Show work please.

yan [13]

Given:

$$\frac{x+4}{x-1}-\frac{5}{x^{2}-1}$

To find:

The simplified rational expression by subtraction.

Solution:

Let us factor $x^2-1$ . It can be written as $x^2-1^2$ .

$x^2-1^2=(x-1)(x+1)$ using algebraic identity.

$$\frac{x+4}{x-1}-\frac{5}{x^{2}-1}=\frac{x+4}{x-1}-\frac{5}{(x+1)(x-1)}$

LCM of $x-1,(x+1)(x-1)=(x+1)(x-1)$

Make the denominators same using LCM.

Multiply and divide the first term by (x + 1) to make the denominator same.

$$=\frac{(x+4)(x+1)}{(x-1)(x+1)}-\frac{5}{(x-1)(x+1)}$

Now, denominators are same, you can subtract the fractions.

$$=\frac{(x+4)(x+1)-5}{(x-1)(x+1)}$

Expand $(x+4)(x+1)-5$ .

$$=\frac{x^2+4x+x+4-5}{(x-1)(x+1)}$

$$=\frac{x^{2}+5 x-1}{(x-1)(x+1)}$

$$\frac{x+4}{x-1}-\frac{5}{x^{2}-1}=\frac{x^{2}+5 x-1}{(x-1)(x+1)}$

6 0

3 years ago