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rusak2 [61]
3 years ago
11

john is thinking of a number in the hundred thousands.The first digit is equal to the number of digits in the number.The number

has twenty tens and twice as many thousands.The number of ones is an odd number that os less than 5 and greater than the digit in the hundreds place. What is Johns number ?
Mathematics
1 answer:
scoundrel [369]3 years ago
5 0
36.3 Johns number sub or add or divid or multication
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The measures of two sides of a triangle are 4in and 13in. Find all possible values that the third side of this triangle can be?
ElenaW [278]

Answer:

9 < x < 17 is the possible length of the third side of a triangle.

Step-by-step explanation:

The Triangle Inequality theorem defines that if we are given two sides of a triangle, the sum of any two given sides of a triangle must be greater than the measure of the 3rd side.

Given the two sides of the triangle

  • 4 in
  • 13 in

Let 'x' be the length of 3rd size.

According to the Triangle Inequality theorem,

The difference of two sides < x < The sum of two sides

13 - 4 < x < 13+4

9 < x < 17

Therefore, 9 < x < 17 is the possible length of the third side of a triangle.

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3 years ago
Please help<br> log(8)10 - log(8) -3x = 1
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3 years ago
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Chantal is building a fence around her swimming pool. The pool is 25 ft long and12 ft wide, and she wants a 6-ft wide rectangula
Alex_Xolod [135]
25 /12*6 =12.5 or thats what i got 
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3 years ago
Write an equation of the line that passes through the given point and is parallel to the given line.
9966 [12]

Answer : <em>Equation of line is</em> y=Equation of line is y=\frac{2}{3}x+\frac{-5}{3}

Step-by-step explanation:

Theory :

Equation of line is given as y = mx + c.

Where, m is slope and c is y intercepted.

Slope of given line : y = \frac{2}{3}x+1 is m= \frac{2}{3}

We know that line : y = \frac{2}{3}x+1 is parallel to equation of target line.

therefore, slope of target line will be \frac{2}{3}.

we write equation of target line as y= \frac{2}{3}x+c

Now, It is given that target line passes through point ( -5,-2)

hence, point ( -5,-2) satisfy the target line's equation.

we get,

y= \frac{2}{3}x+c

-2= \frac{2}{3} \times -5+ c

-5= \frac{-10}{3}+c

c= \frac{-5}{3}

thus, Equation of line is y=Equation of line is y=\frac{2}{3}x+\frac{-5}{3}

7 0
3 years ago
How do I simplify an expression
Sladkaya [172]
Start with parentheses first
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