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Gre4nikov [31]
2 years ago
14

Quadrilaterals and other polygons

Mathematics
2 answers:
Vinvika [58]2 years ago
4 0

Answer:

B

Step-by-step explanation:

Brut [27]2 years ago
4 0
I got B too and I got it right on my test
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Write a ratio that is equivalent to 3:5, other than 3:5 itself
natulia [17]

Answer:

9:15

Step-by-step explanation:

\frac{3*3}{5*3}=\frac{9}{15}=9:15

7 0
3 years ago
What is the answer to 2/5(10p-15)=14?
satela [25.4K]

Answer:

P = 5

Step-by-step explanation:

2/5(10p) - 2/5(15)= 14

20p/5 - 30/5= 14

4p - 6= 14

4p = 20

p=5

8 0
3 years ago
Plsss help it due today I don’t understand how to do this plssss don’t just take the points
tensa zangetsu [6.8K]

Answer:

d a m i dont even know this

Step-by-step explanation:

4 0
3 years ago
Q2.
Nimfa-mama [501]

Answer:

see below

Step-by-step explanation:

A = {8, 9, 10, 11, 12, 13, 14} and   B = {2, 4, 6, 8, 10, 12, 14, 16, 18}

----------------

(i) List down the elements of A’ and B’

{8, 9, 10, 11, 12, 13, 14, 2, 4, 6, 8, 10, 12, 14, 16, 18} - this is the elements of both sets

----------

(ii) Are sets A - B and B - A equal sets?

A-B= {9, 11, 13}

B-A= {2, 4, 6, 16, 18}

These are not equal as we can see

----------

(iii) Find and compare the sets (AUB)’ and A’∩B’ and share your observations

A∪B= {2, 4, 6, 8, 9, 10, 11, 12, 13, 14, 16, 18}- union included all elements of both sets

A∩B= {8, 10, 12, 14} - intersection only includes common elements

7 0
3 years ago
Answer questions 13. And 14. Please! Show minimal work...
ale4655 [162]

13. The equation of the given function is y=4sin[\frac{(t-\frac{4}{3})}{2}]-2

14. The equation of the cotangent function is y=cot[2(t-\frac{1}{3})]+2

Step-by-step explanation:

Let us revise the transformation of the trigonometric function:

y = a f[b(x + c)] + d, where

  • Amplitude is a
  • f represents the trigonometry function
  • Period is 2π/b
  • Phase shift is c (positive is to the left)
  • Vertical shift is d

13.

∵ y = a sin( \frac{2\pi t}{T} ), where a is the amplitude

   and T is the wave in seconds

∵ The amplitude is 4

∴ a = 4

∵ The period is 4π

∴ T = 4π

From the rules above

∵ The period is 2π/b

∴ T = \frac{2\pi }{B}

∴ 4π = \frac{2\pi }{b}

- By using cross multiplication

∴ 4π(b) = 2π

- Divide both sides by 4π

∴ b = \frac{1}{2}

∵ The phase shift is -\frac{4}{3}\pi

∵ c is the phase shift

∴ c = -\frac{4}{3}\pi

∵ The vertical shift is -2

∵ d is the vertical shift

∴ d = -2

Now substitutes the values of a, b, c and d in the form of the equation below

∵ y = a sin[b(t + c)] + d

∴ y=4sin[\frac{1}{2}(t-\frac{4}{3})]-2

You can write it as y=4sin[\frac{(t-\frac{4}{3})}{2}]-2

The equation of the given function is y=4sin[\frac{(t-\frac{4}{3})}{2}]-2

14.

y = cot[b(t + c)] + d

∵ The period = π

∵ The period is 2π/b

- Equate π by 2π/b to find b

∴ π = \frac{2\pi }{b}

- By using cross multiplication

∴ π(b) = 2π

- Divide both sides by π

∴ b = 2

∵ The phase shift is -\frac{1}{3}\pi

∵ c is the phase shift

∴ c = -\frac{1}{3}\pi

∵ The vertical shift is 2

∵ d is the vertical shift

∴ d = 2

Now substitutes the values of b, c and d in the form of the equation below

∵ y = cot[b(t + c)] + d

∴ y=cot[2(t-\frac{1}{3})]+2

The equation of the cotangent function is y=cot[2(t-\frac{1}{3})]+2

Learn more:

You can learn more about trigonometry function in brainly.com/question/3568205

#LearnwithBrainly

5 0
3 years ago
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