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3 years ago

Number 20 please!!!!!!!!

Mathematics

1 answer:

masha68 [24]3 years ago

4 0

Answer:

y[1] = 14
y[n+1] = y[n] -5 . . . . n ≥ 1

Step-by-step explanation:

The first element in the table is 14, so that is the initial condition for the recursive formula. y[1] = 14

Each table element is 5 less than the previous one, so that is the recursive rule. y[n+1] = y[n] -5

As shown by your markings, you have already figured out the relationship between y-values. All you have to do is write that as a recursive rule. If you use y[n] as the current value, then the previous one is y[n-1]. (The current value is 5 less than the previous one.)

Above, I have used y[n+1] as the next value and y[n] as the current value. (The next value is 5 less than the current one.) Either way, the set of rules generates the same sequence. No doubt, your curriculum materials prefer one form over the other. Use that.

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What is 1/3 - 1/9 simplified?

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2/9 Is your simplified fraction! Have a great day!

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4 years ago

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Find the length of side x in the figure. Round to the nearest whole number, if necessary

LekaFEV [45]

Use the Pythagorean Theorem
a^2 + b^2 = c^2
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3 years ago

A bag contains 5 red apples and 4 yellow apples. 4 apples are selected at random. Find the probability of selecting 2 red apples

Oksi-84 [34.3K]

Assuming that the apples are not tossed back into the bag after drawing them.

Total of 9 apples.

1st draw yell, 4/9

2nd draw yell, 3/8

3rd draw red, 5/7

4th draw red, 4/6

$\frac{4}{9} * \frac{3}{8} * \frac{5}{7} * \frac{4}{6} = \frac{240}{3024} \\ \\ = \frac{5}{63}$

7 0

4 years ago

if a runner finishes the 26.2. mille race in 4 hours and 37 mins and Wilson kipping finish in 4 minutes and 43 seconds per mile

Neporo4naja [7]

Answer

a) Wilson Kipsang is 7.046 miles per hour faster than the average runner.

Solution is presented below under Explanation.

b) Wilson Kipsang is 2.24 times faster than the average runner.

c) When the average runner is at mile 6, Kipsang will be at mile 13.45.

d) Kipsang's record time = 2 hours, 3 minutes, 34.6 seconds

Explanation

To solve this, we will calculate the speed of the average runner and then the speed of Wilson Kipsang

Speed = (Distance/Time)

For the average runner

Distance = 26.2 miles

Time = 4 hours 37 mins = 4 hours + (37/60) = 4.617 hours

Speed = (Distance/Time)

Speed = (26.2/4.617)

Speed = 5.675 miles per hour

For Wilson Kipsang

Distance = 1 mile

Time = 4 minutes 43 seconds = (4/60) + (43/3600) = 0.0667 + 0.01194 = 0.0786 hour

Speed = (Distance/Time)

Speed = (1/0.0786) = 12.721 miles per hour

So, now, we are asked to find how much faster than the average runner is Wilson Kipsang

Wilson Kipsang's speed = 12.721 miles per hour

Average runner's speed = 5.675 miles per hour

Wilson Kipsang is faster than the average runner by

(12.721 - 5.676) = 7.046 miles per hour

b) We are asked to find how many times faster than the average runner Wilson Kipsang is.

Let the number of times he is faster than the average runner be x

Wilson Kipsang's speed = 12.721 miles per hour

Average runner's speed = 5.675 miles per hour

(5.675) (x) = (12.721)

Divide both sides by 5.675

x = (12.721/5.675)

x = 2.24 times

c) If the average runner is at mile 6, where would Kipsang be?

To do this, we will find the time it takes the average runner to be at mile 6, then use that time to find where Kipsang would be.

Speed = (Distance/Time)

By cross multiplying, we see that

Time = (Distance/Speed)

For the average runner

Distance = 6 miles

Speed = 5.675 miles per hour

Time = (Distance/Speed)

Time = (6/5.675) = 1.057 hours

For Wilson Kipsang,

Speed = (Distance/Time)

By cross multiplying

Distance = (Speed) (Time)

Speed = 12.721 miles per hour

Time = 1.057 hours

Distance = (Speed) (Time)

Distance = (12.721) (1.057)

Distance = 13.45 miles

d) We were told that for Kipsang

1 mile = 4 minutes 43 seconds

26.2 miles = 26.2 (4 minutes 43 seconds)

26.2 miles = 26.2 (283 seconds) = 7414.6 seconds

We can then convert this further

7414.6 seconds = 2 hours, 3 minutes, 34.6 seconds

Hope this Helps!!!

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1 year ago

ABC ~ DEF<br> What is the value for x, the length of side BC?

Stella [2.4K]

Answer:

17.5

Step-by-step explanation:

as the triangles are similar, when oriented in the same direction they have the same angles, and the lengths of all sides of DEF are the lengths of the sides of ABC but multiplied by the same scaling factor f for all sides.

so, we see that

A ~ D

B ~ E

C ~ F

and therefore

AB ~ DE

BC ~ EF

CA ~ FD

that means

DE = AB × f

EF = BC × f

FD = CA × f

we know DE and AB.

so,

4 = 10 × f

f = 4/10 = 2/5

and now we know

EF = 7 = BC × f

BC = 7/f = (7/1) / (2/5) = (5×7)/(2×1) = 35/2 = 17.5

7 0

3 years ago