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Verdich [7]
3 years ago
13

Mercedes has a spool containing 15 2/3 inches of ribbon she cut a length of 6 1/2 inch to tie a bow how much ribbon is left on t

he school
Mathematics
2 answers:
mr_godi [17]3 years ago
7 0

Answer:

9 1/6 is the asnwer hope this helped :)

Step-by-step explanation:

Blizzard [7]3 years ago
6 0

Answer: The answer is...

9 1/6

Step-by-step explanation:

Subtract the fractions by first finding a common denominator. Then, write equivalent fractions, subtract the whole numbers and the numerators. Write the answer in simplest form.

15 2/3- 6 1/2

15 4/6 - 6 3/6= 9 1/6

Mercedes has 9  1 /6  inches  of ribbon left.

<em><u>I hope yo have a productive day</u></em>

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Which is the graph of x^2/16 + y^2/ 9 =1
jeka94

Answer:

B

Step-by-step explanation:

you can figure this out by replace the x and y with any one of the x, y positions and if the answer is 1 it's correct.

I tried 0^2/16+3^2/9 and I got 1.

I tried this with the first two but they didn't work.

6 0
3 years ago
Find m&lt;v 36x-1 =29x+1​
lina2011 [118]

Answer:

M<36×-=36=29×+1=29.....

5 0
3 years ago
Connecticut families were asked how much they spent weekly on groceries. Using the following data, construct and interpret a 95%
Amanda [17]

Answer:

The 95% confidence interval for the population mean amount spent on groceries by Connecticut families is ($73.20, $280.21).

Step-by-step explanation:

The data for the amount of money spent weekly on groceries is as follows:

S = {210, 23, 350, 112, 27, 175, 275, 50, 95, 450}

<em>n</em> = 10

Compute the sample mean and sample standard deviation:

\bar x =\frac{1}{n}\cdot\sum X=\frac{ 1767 }{ 10 }= 176.7

s= \sqrt{ \frac{ \sum{\left(x_i - \overline{x}\right)^2 }}{n-1} }       = \sqrt{ \frac{ 188448.1 }{ 10 - 1} } \approx 144.702

It is assumed that the data come from a normal distribution.

Since the population standard deviation is not known, use a <em>t</em> confidence interval.

The critical value of <em>t</em> for 95% confidence level and degrees of freedom = n - 1 = 10 - 1 = 9 is:

t_{\alpha/2, (n-1)}=t_{0.05/2, (10-1)}=t_{0.025, 9}=2.262

*Use a <em>t</em>-table.

Compute the 95% confidence interval for the population mean amount spent on groceries by Connecticut families as follows:

CI=\bar x\pm t_{\alpha/2, (n-1)}\cdot\ \frac{s}{\sqrt{n}}

     =176.7\pm 2.262\cdot\ \frac{144.702}{\sqrt{10}}\\\\=176.7\pm 103.5064\\\\=(73.1936, 280.2064)\\\\\approx (73.20, 280.21)

Thus, the 95% confidence interval for the population mean amount spent on groceries by Connecticut families is ($73.20, $280.21).

7 0
3 years ago
14.4% of 72.5 is what number?
Elina [12.6K]
This is very simple to do. Take out your calculator and insert 14.4. However, move the decimal two places to the left to get .144, and multiply it by 72.5 to get your answer of 10.44.
5 0
3 years ago
Jenna is at a fair with four friends. They all want to ride the roller coaster, but only three people can fit in a car. How many
pav-90 [236]

Answer:

They can make 10 different groups of three.

Step-by-step explanation:

The order in which the people are in the car is not important, so we use the combinations formula to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

How many different groups of three can the five of them make?

Combinations of 3 from a set of 5. So

C_{5,3} = \frac{5!}{3!(5-3)!} = 10

They can make 10 different groups of three.

6 0
2 years ago
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