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masya89 [10]
3 years ago
7

What is the period of the function?

Mathematics
1 answer:
uranmaximum [27]3 years ago
3 0

Answer:

2

Step-by-step explanation:

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I need a tutor who can answer more than 1 question.if not im sorry i have to end the session
nirvana33 [79]

Part A.

The area of a triangle is given by the product of its base and the height relative to that base.

Since these triangles have the same base b and same height h, they have the same area.

Part B.

The area of a rectangle or parallelogram is given by the product of base and height. Since these figures have the same base and height, they have the same area.

Part C.

These figures have different shapes, so we can't affirm that they have the same area.

Part D.

The height shown in the image is not the height relative to side b, therefore we can't affirm that the triangles have the same area.

4 0
1 year ago
Chords AB and CD intersect at point E, AE = 10, EB = 4, and CE = 8. Therefore, ED =
Genrish500 [490]
So here is how we are going to find out what is ED. 
Based on the given figure, it states that, AE is 10, and EB is 4 and CE is 8.
So, <span>(AE/CE)=(ED/EB)
10/8 = ED/4 <<multiply both sides by the common denominator which is 8 and the result would be:
80/8 = 8ED/4
10 = 2ED <<divide both sides by 2 and we get
ED = 5.
Therefore, the measurement of ED is 5. 
Hope this answer helps. Let me know if you need more help next time!</span>
5 0
3 years ago
Read 2 more answers
Carl is twice as old as Ginger. If Carl were 2 years younger and Ginger were 3 years older, the difference of their ages would b
Mashcka [7]
Ginger would be 8 years old.
8+3=11
16-2=14
16/2=8
3 0
3 years ago
ANSWER ASASPP PLSSSSSS
podryga [215]

Answer:

There are 14 problems worth 5 points and 15 problems worth 2 points.

Step-by-step explanation:

Hope this helped have a good day :)

5 0
2 years ago
Someone please help with this?!!
Vika [28.1K]
Well, it says to use a calculator to calculate them. So a calculator I would highly recommend is the Desmos graphing calculator.
7 0
3 years ago
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