Answer:
1680 ways
Step-by-step explanation:
In this question, we are tasked with finding the number of ways in which we can select 4 trips out of 8 to make today.
Let us label the the trips we are to select as A B C D, one after the other
For selection A, we have 8 different trips waiting to be selected
For selection B, we have 7 trips to select from
For C, we have 6 to select from
while for D, we have 5 to select from. Thus, the total number of ways in which we can select these trips can be calculated as = 8 × 7× 6× 5 = 1,680 ways
Answer: um, you mean 10 + 122=132, the second one is n>4 if you want step by step look below:
Let's solve your inequality step-by-step.
3n>12
Step 1: Divide both sides by 3.
3n/3 > 12/3
n>4
You can use a numberline too.
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Define x:
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Let x be the number of students in the second class:
⇒second class = x
There are 3 more students in the first class than in the second class:
⇒first class = x + 3
There are 2 more students in the third class than in the second class:
⇒third class = x + 2
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Expression for each class:
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First class = x + 3
Second class = x
Third class = x + 2
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Expression for total number of students:
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Total = x + 3 + x + x + 2
Total = 3x + 5
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Find x:
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There are 80 students in total, so
3x + 5 = 80
3x = 75
x = 25
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Find the number of students in each class:
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First class = x + 3 = 25 + 3 = 28
Second class = x = 25
Third class = x + 2 = 25 + 2 = 27
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Answer: There are 25 students in the second class.
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Answer:
The answer is B
Step-by-step explanation:
7.4*3.1=22.94
5*3.1=15.5
7.4*5=37
22.94+22.94+15.5+15.5+37+37=150.88
The slope is rise/run so 2/2
