Answer:
64/19
OR
3 7/19
depending on how you need to write it
Step-by-step explanation:
Answer:
Step-by-step explanation:
First,You have to realize that if you multiply the amount of food by something, you multiply the amount of calories. if some piece of food is 100 calories what happens if you eat 2? you get 2 times that number of calories. Same fi you eat half of one of that kind of food. You get half the amount of calories.
Here he makes 1 1/2 (one and a half) times the amount. Now, if this is confusing you just need to realize that multiplying by this is the same as multiplying by 1+1/2. Say, again, a piece of food is 100 calories. Multiplying it by this would look like the following.
100(1+1/2)
100*1 + 100*1/2
100+50
150
So if you ever have a mixed number like this you could split it up into an addition problem and then distribute hat you're multiplying. Another solution is to multiply by the improper fraction, which here is 3/2, so 100*3/2=150 as well. Let me know if you don't get how to get the improper fraction or how to multiply fractions.
Now, super simple, just multiply the calories by that number.
310(1+1/2) = 310(3/2)
310 + 155 = 930/2
465 = 465
Kinda showed how to multiply by fractions, still if you don't get it let me know.
Answer: AAS
Step-by-step explanation:
So for this question, we're asked to find the quadrant in which the angle of data lies and were given to conditions were given. Sign of data is less than zero, and we're given that tangent of data is also less than zero. Now I have an acronym to remember which Trig functions air positive in each quadrant. . And in the first quadrant we have that all the trig functions are positive. In the second quadrant, we have that sign and co seeking are positive. And the third quadrant we have tangent and co tangent are positive. And in the final quadrant, Fourth Quadrant we have co sign and seeking are positive. So our first condition says the sign of data is less than zero. Of course, that means it's negative, so it cannot be quadrant one or quadrant two. It can't be those because here in Quadrant one, we have that all the trick functions air positive and the second quadrant we have that sign. If data is a positive, so we're between Squadron three and quadrant four now. The second condition says the tangent of data is also less than zero now in Quadrant three. We have that tangent of data is positive, so it cannot be quadrant three, so our r final answer is quadrant four, where co sign and seek in are positive.
Answer:
what should we be finding?
