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marin [14]
3 years ago
5

For a certain model of car the distance d required to stop the vehicle if it is traveling at v mi/h is given by the formula d =

v + v2 20 where d is measured in feet. kerry wants her stopping distance not to exceed 75 ft. at what range of speeds (in mi/h) can she travel? (enter your answer using interval notation.) c
Mathematics
1 answer:
enyata [817]3 years ago
8 0
Given that <span>For a certain model of car the distance d required to stop the vehicle if it is traveling at v mi/h is given by the formula d=v+\frac{v^2}{20}, where [tex]d is measured in feet.

If Kerry wants her stopping distance not to exceed 75 ft, then the range of speeds (in mi/h) can she travel is obtained as follows:

v+ \frac{v^2}{20} \leq75 \\  \\ 20v+v^2\leq1,500 \\  \\ v^2+20v+100\leq1,500+100 \\  \\ (v+10)^2\leq1,600 \\  \\ |v+10|\leq\sqrt{1,600} \\  \\ -40\leq v+10\leq40 \\  \\ -40-10\leqv\leq v\leq40-10 \\  \\ -50\leq v\leq30

Therefore, the range of speed she can travel is v\leq30\ mi/hr
</span>
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Because the ratio of changes in y to changes in x is constant (-5/1) = -5, you know the function is linear. To write the equation, you can use the slope-intercept form, since you know the slope (-5) and the table shows the y-intercept: (x, y) = (0, -1).

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2 years ago
What is the sum1,000+2,000=
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\textsf{Apply radical rule} \quad \sqrt{a^2}=a, \quad a \geq 0:

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7 0
2 years ago
Half an hour after leaving her house Beverly was 20 miles from home. At this point she merged onto the highway and was traveling
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Answer:

1. 45.71 miles

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3. 89.43 miles

4. 0.79 hr

5. 0.025 hr

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3. in 1.85 hrs beverly will have travvelld;

⇒ (20 miles in 0.5 hr ) + (1.35 hr at speed 51.43 miles/hr)

⇒ 20 + 69.43 = 89.43 miles

4. Time taken to get to 35 miles

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⇒ 0.5hr + (15/51.43) hr = 0.79 hr

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⇒ time = 0.025 hr

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