You have to find the mean median and mode with the three day period and the four day period and compare them.
I believe that unless I did something wrong, the answer is B!
Hope this helps,
CK :)
Answer:
Step-by-step explanation:
180 - 152 = 28
2x + 28 = 180
2x = 152
x = 76
Answer:
The probability that the sample mean will lie within 2 values of μ is 0.9544.
Step-by-step explanation:
Here
- the sample size is given as 100
- the standard deviation is 10
The probability that the sample mean lies with 2 of the value of μ is given as
![P(| \bar{X}-\mu|](https://tex.z-dn.net/?f=P%28%7C%20%5Cbar%7BX%7D-%5Cmu%7C%3C2%29%5C%5CP%28-2%3C%5Cbar%7BX%7D-%5Cmu%3C2%29%5C%5C)
Here converting the values in z form gives
![P(-2](https://tex.z-dn.net/?f=P%28-2%3C%5Cbar%7BX%7D-%5Cmu%3C2%29%5C%5CP%28%5Cfrac%7B-2%7D%7B%5Cfrac%7B%5Csigma%7D%20%7B%5Csqrt%7Bn%7D%7D%7D%3C%5Cfrac%7B%5Cbar%7BX%7D-%5Cmu%7D%7B%5Cfrac%7B%5Csigma%7D%20%7B%5Csqrt%7Bn%7D%7D%7D%3C%5Cfrac%7B2%7D%7B%5Cfrac%7B%5Csigma%7D%20%7B%5Csqrt%7Bn%7D%7D%7D%29)
Substituting values
![P(-2](https://tex.z-dn.net/?f=P%28-2%3C%5Cbar%7BX%7D-%5Cmu%3C2%29%5C%5CP%28%5Cfrac%7B-2%7D%7B%5Cfrac%7B10%7D%20%7B%5Csqrt%7B100%7D%7D%7D%3Cz%3C%5Cfrac%7B2%7D%7B%5Cfrac%7B10%7D%20%7B%5Csqrt%7B100%7D%7D%7D%29%5C%5CP%28-2%3Cz%3C2%29%3DP%28z%3C2%29-P%28z%3C-2%29)
From z table
![P(z\leq 2)=0.9772\\P(z\leq -2)=0.0228\\P(-2\leq z\leq 2)=P(z\leq 2)-P(z\leq -2)\\P(-2\leq z\leq 2)=0.9772-0.0228\\P(-2\leq z\leq 2)=0.9544\\](https://tex.z-dn.net/?f=P%28z%5Cleq%202%29%3D0.9772%5C%5CP%28z%5Cleq%20-2%29%3D0.0228%5C%5CP%28-2%5Cleq%20z%5Cleq%202%29%3DP%28z%5Cleq%202%29-P%28z%5Cleq%20-2%29%5C%5CP%28-2%5Cleq%20z%5Cleq%202%29%3D0.9772-0.0228%5C%5CP%28-2%5Cleq%20z%5Cleq%202%29%3D0.9544%5C%5C)
So the probability that the sample mean will lie within 2 values of μ is 0.9544.
The answer in simplest form is 1/4.
Answer:
40 girls
Step-by-step explanation:
if you multiply 5 times 10, then you have to multiply the other side by 10 too. So 5 times 10 equals 50, and 4 times 10 equals 40.
40+50+=90.