-4x+3y=-13 -8x+3y=-17 solve by elimanation
1 answer:
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Answer:
and
Step-by-step explanation:
It is given that the normal body temperature is .
A temperature 'x' that differs from normal by at least is considered unhealthy. So the inequality to represent such situation is,
It can be further written as,
and
and
and
So the inequality to represent such condition is and
.
Answer:
This is proved by ASA congruent rule.
Step-by-step explanation:
Given KLMN is a parallelogram, and that the bisectors of ∠K and ∠L meet at A. we have to prove that A is equidistant from LM and KN i.e we have to prove that AP=AQ
we know that the diagonals of parallelogram bisect each other therefore the the bisectors of ∠K and ∠L must be the diagonals.
In ΔAPN and ΔAQL
∠PNA=∠ALQ (∵alternate angles)
AN=AL (∵diagonals of parallelogram bisect each other)
∠PAN=∠LAQ (∵vertically opposite angles)
∴ By ASA rule ΔAPN ≅ ΔAQL
Hence, by CPCT i.e Corresponding parts of congruent triangles PA=AQ
Hence, A is equidistant from LM and KN.
