Answer:
See Below.
Step-by-step explanation:
We are given that ΔAPB and ΔAQC are equilateral triangles.
And we want to prove that PC = BQ.
Since ΔAPB and ΔAQC are equilateral triangles, this means that:
Likewise:
Since they all measure 60°.
Note that ∠PAC is the addition of the angles ∠PAB and ∠BAC. So:
Likewise:
Since ∠QAC ≅ ∠PAB:
And by substitution:
Thus:
Then by SAS Congruence:
And by CPCTC:
Answer:
Step-by-step explanation:
For this case we have the following expression:
For this case we can apply the following property:
And we can rewrite the following expression like this:
And we can rewrite like this our expression:
Now we can use the following property:
And we got this:
And now we can apply the following property:
And we got this:
And that would be our final answer on this case.