Answer:
The maximum height of the projectile is 90 ft
Step-by-step explanation:
Here, we want to get the maximum height reached by the projectile
The answer here will be the y-coordinate value of the vertex form of the given equation
so firstly, we have to write the equation in the vertex form
We have this as;
y = -16t^2 + 64t + 26
That will be;
y = a(x-h)^2 + k
y = -16(x-2)^2 + 90
where the vertex of the equation is;
(-h,k)
K
in this case is 90 and thus, that is the maximum height of the projectile
Answer:
3/2 or 1.5
Step-by-step explanation:
Convert (-3 1/3) to -10/3
Now its -5/(-10/3)
The 3 is multiplied by the -5
(-5)(3)/(-10)
=(-15)/(-10)
The negatives cancel and it reduces to 3/2
We are given with the equation <span>d + 3n = 1 and asked to solve for n in the problem. the first step is to apply subtraction property by subtracting d to each side of the equation. Hence 3 n = 1 - d. next, we use division property by dividing the whole equation by 3. hence n = (1 - d) / 3</span>