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Gekata [30.6K]
3 years ago
6

Find the slope of the line that passes through the pair of points (6, 7) and (9, 2). User: Find the slope of the line that passe

s through the pair of points (17, 9) and (5, 29).
Mathematics
1 answer:
DaniilM [7]3 years ago
4 0
If we have two points;
A(x₁,y₁)
B(x₂,y₂)

m=slope

m=(y₂-y₁) / (x₂-x₁)

Therefore:
(6,7)
(9,2)

m=(2-7) / (9-6)=-5/3.

Solution₁= the solpe of the line that passes through the poitns (6,7) and (9,2) is m=-5/3.

(17,9)
(5,29)

m=(29-9) / (5-17)=20/-12=-5/3

Solution ₂: the slope of the line that passes through the  parir of points (17,9) and (5,29) is m=-5/3

Therefore, both lines have the same slope.
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Mr. Moore has 21 feet of wallpaper he cuts it into sections that are each 3 feet long how many
9966 [12]

Total = 21 feet

if each is 3 feet

21/3 = 7

Therefore, there are 7 sections

5 0
3 years ago
Write an equation for the parent function y = x^ 2 stretched by a factor of 6 and shifted down 4 units?
Sunny_sXe [5.5K]

Answer:

 

Translations

y = f (x) + k up k units

y = f (x) - k down k units

y = f (x + h) left h units

y = f (x - h) right h units

Stretches/Shrinks

y = m·f (x) stretch vertically by a factor of m

y = ·f (x) shrink vertically by a factor of m (stretch by  

y = f (x) stretch horizonally by a factor of n

y = f (nx) shrink horizontally by a factor of n (stretch by )

Reflections

y = - f (x) reflect over x-axis (over line y = 0)

y = f (- x) reflect over y-axis (over line x = 0)

x = f (y) reflect over line y = x

Hope this helps

Step-by-step explanation:

5 0
3 years ago
Solve log 4x + log 13 = 0. Round to the nearest thousandth if necessary. a.0.019 b. 52 c.3.25 d. 0.311 Mathematics
kumpel [21]
Log4 + logX + log13 = 0
logX = -log13 - log4
logX = -1.716
x= 10^[-1.716]
x= 0.019 A
6 0
3 years ago
The hypotenuese of an isosceles right triangle is 13 inches. The midpoints of its sides are connected to form an inscribed trian
Georgia [21]

Answer:

The Sum of the areas of theses triangles is 169/3.

Step-by-step explanation:

Consider the provided information.

The hypotenuse of an isosceles right triangle is 13 inches.

Therefore,

x^2+x^2=169\\2x^2=169\\x=\frac{13}{\sqrt{2} }

Then the area of isosceles right triangle will be: A=\frac{1}{2} x^2

Therefore the area is: A=\frac{169}{4}

It is given that sum of the area of these triangles if this process is continued infinitely.

We can find the sum of the area using infinite geometric series formula.

S=\frac{a}{1-r}

Substitute a=\frac{169}{4} \ and\ r=\frac{1}{4} in above formula.

S=\frac{\frac{169}{4}}{1-\frac{1}{4}}

S=\frac{\frac{169}{4}}{\frac{3}{4}}

S=\frac{169}{3}

Hence, the Sum of the areas of theses triangles is 169/3.

7 0
3 years ago
How many solutions does the graphed system of equations have:
Alex17521 [72]

Answer:

since the lines don't intersect there is no solution.


8 0
3 years ago
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