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Pavel [41]
3 years ago
9

Is a cub a polygon ?why or why not

Mathematics
1 answer:
Vladimir79 [104]3 years ago
6 0
A cube<span> is </span>not<span> a </span>polygon<span>. </span>Polygons<span> are flat, plane figures. A </span>cube<span> is a 3- di mensional solid figure.</span>
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Hey guys! ima just randomly thank people and rate their answers! plus fe points!
Softa [21]

Answer:

cool

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Given that P = (5, 8) and Q = (6, 9), find the component form and magnitude of vector PQ.
max2010maxim [7]

Answer:

<1 ,1>..., square root of two

Step-by-step explanation:

Component of vector PQ...,

; Q - P...where you subtract the x coordinate of Q by the x coordinate of P and the same for the y coordinate

; <(6-5),(9-8)>

; < 1,1 >

And the magnitude of PQ...,

;square root of( 1^2 + 1^2 )

;square root of 2

3 0
3 years ago
Orange M&amp;M’s: The M&amp;M’s web site says that 20% of milk chocolate M&amp;M’s are orange. Let’s assume this is true and set
SOVA2 [1]

Answer:

The correct option is (A).

Step-by-step explanation:

Let <em>X</em> = number of orange  milk chocolate M&M’s.

The proportion of orange milk chocolate M&M’s is, <em>p</em> = 0.20.

The number of candies in a small bag of milk chocolate M&M’s is, <em>n</em> = 55.

The event of an milk chocolate M&M being orange is independent of the other candies.

The random variable <em>X</em> follows a Binomial distribution with parameter <em>n</em> = 55 and <em>p</em> = 0.20.

The expected value of a Binomial random variable is:

E(X)=np

Compute the expected number of orange  milk chocolate M&M’s in a bag of 55 candies as follows:

E(X)=np

         =55\times 0.20\\=11

It is provided that in a randomly selected bag of milk chocolate M&M's there were 14 orange ones, i.e. the proportion of orange milk chocolate M&M's in a random bag was 25.5%.

This proportion is not surprising.

This is because the average number of orange milk chocolate M&M’s in a bag of 55 candies is expected to be 11. So, if a bag has 14 orange milk chocolate M&M’s it is not unusual at all.

All unusual events have a very low probability, i.e. less than 0.05.

Compute the probability of P (X ≥ 14) as follows:

P(X\geq 14)=\sum\limits^{55}_{x=14}{{55\choose x}0.20^{x}(1-0.20)^{55-x}}

                 =0.1968

The probability of having 14 or more orange candies in a bag of milk chocolate M&M’s is 0.1968.

This probability is quite larger than 0.05.

Thus, the correct option is (A).

4 0
3 years ago
How do I simplify the expression
stiks02 [169]
ANSWER: ab√3ac

Is this enough for you ?

5 0
2 years ago
Suppose that a class contains 15 boys and 30 girls, and that 10 students are to be selected at random for a special assignment.
natka813 [3]
Prob of selected students times prob of selecting boys times prob of selecting 3 boys
total students = 15b + 30g = 45 students

1. 10s/45t = 0.22
2. 15b/45t = 0.33
3. 3b/15b = 0.2

0.22×0.33×0.2=0.0148

1.48%

I'm not sure 100%... double check answer please
3 0
3 years ago
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