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slamgirl [31]
3 years ago
13

GEOMETRY HELP! SIMILAR TRIANGLE!

Mathematics
1 answer:
mylen [45]3 years ago
7 0
1) Yes
2)B. AA
3) The angles are congruent and both are right triangles.
4) 90
5) 60
6) 60
7) 90
9) 4
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What is the coordinate?
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Remember that the equation of a circle is:
(x - h)^{2} + (y - k)^{2} =  r^{2}
Where (h, k) is the center and r is the radius.
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x^{2} - 6x +  y^{2} - 10y = 56

Complete the square. We must do this for x² - 6x and y² - 10y separately.

x² - 6x
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Square -3 to get 9. Add 9,
x² - 6x + 9

Because we've added 9 on one side of the equation, we have to remember to do the same on the other side.

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Now factor x² - 6x + 9 to get (x - 3)² and do the same thing with y² - 10y.

y² - 10y
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Square -5 to get 25.
Add 25 on both sides.

(x - 3)^{2}+ y^{2} - 10y + 25= 90

Factor y² - 10y + 25 to get (y - 5)²

(x - 3)^{2}+ (y - 5)^{2} = 90

Now our equation is in the correct form. We can easily see that h is 3 and k is 5. (not negative because the original equation has -h and -k so you must multiply -1 to it)

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Solutions for x2 −22x+121=49
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The answer is d I think
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