Thank you for asking this question. Here is your answer:
M = y2 - y1/x2 - X1 = M
= 290 - 210/120 - 80
M = 80/40
M = 2
Now we will consider y intercept
y = mx + b
210 = 2(80) + b
210 = 160 + b
b = 210 - 160
= 50
Now we will combine everything in order to get the answer.
y = 2x + 50
y = 2(60) + 50
y = 120 + 50
y = 170
So the final answer for this question is $170.
If there is any confusion please leave a comment below.
Read more on Brainly.in - https://brainly.in/question/6262493#readmore
We are given a line with the following data:
r-value = 0.657 (r)
standard deviation of x-coordinates = 2.445 (Sx)
standard deviation of y-coordinates = 9.902 (Sy)
We are asked to find the slope of the line up to 3 decimal places.
To find the slope of the line, based on the data that we have, we can use this formula:
slope, b = r * (Sy / Sx)
substitute the values to the formula:
b = 0.657 * ( 9.902 / 2.445 )
Solve for the b.
Therefore, the slope of the line is
b = 2.66078, round off to three decimal places:
b = 2.661 is the slope of the line.
The answer is : X=-7/3-2/3y
the answer is
B.
Stacy’s employer is withholding too little for state income tax.
Answer:
Pumpkins are used as decorations during the fall months.
Pumpkins are used as decorations during the fall months.
Pumpkins are used as decorations during the fall months.
Pumpkins are used as decorations during the fall months.
Pumpkins are used as decorations during the fall months.
Pumpkins are used as decorations during the fall months.
Pumpkins are used as decorations during the fall months.
Pumpkins are used as decorations during the fall months.
Pumpkins are used as decorations during the fall months.
Pumpkins are used as decorations during the fall months.
Pumpkins are used as decorations during the fall months.
Pumpkins are used as decorations during the fall months.
Pumpkins are used as decorations during the fall months.
Pumpkins are used as decorations during the fall months.
Pumpkins are used as decorations during the fall months.
