Answer: 0.0174
Step-by-step explanation:
Given : 
Let x be the random variable that represents the weight of the drumsticks.
We assume that the weight of the drumsticks is normally distributed.
Now, the z-score for x=2.23 ,
Using z-value table , we have
P-value =P(x≥2.23)=P(z≥2.11)=1-P(z<2.11)=1-0.9825708
=0.0174292≈0.0174 [Rounded nearest 4 decimal places]
Hence, the probability of the stick's weight being 2.23 oz or greater = 0.0174
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4/3 (k)(k + 7)(3k + 9)
4/3 (k)(3k^2 + 9k + 21k + 63)
4/3 (k)(3k^2 + 30k + 63)
4/3 (3k^3 +30k + 63)
4k^3 +40k +84
Start by looking at the vertex form of a quadratic function, f(x) = a(x - h)^2 + k. The variables h and k are the values of the vertex. Plug those in to get f(x) = a(x - 4)^2 + 5. To find the variable a, plug in the point given for the x and y values. So, you get (21) = a((8) - 4)^2 + 5. Solve for a algebraically, and you get a = 1. Finally, plug everything in and simplify the equation. You should get that the quadratic function is f(x) = x^2 - 8x + 21. Hope this helps!
Answer:
89.008
Step-by-step explanation:
z = (x– mean)/ standard deviation
x = z * standard deviation + mean
Now, z value for the top 4% of the exams (which is the same as getting a score below the 96%) has to be found using a z table.
In this case z = 1.751
x = 1.751 * 8 + 75
x = 89.008
