The required probability is 
<u>Solution:</u>
Given, a shipment of 11 printers contains 2 that are defective.
We have to find the probability that a sample of size 2, drawn from the 11, will not contain a defective printer.
Now, we know that, 
Probability for first draw to be non-defective 
(total printers = 11; total defective printers = 2)
Probability for second draw to be non defective 
(printers after first slot = 10; total defective printers = 2)
Then, total probability 
With this line, we see that when x is a small negative number, F(x) is a very large negative number, or B.
Remember that F(x) is the same as y. And looking at the pattern of the line, the greater the negative x is, the smaller the negative y is.
C because I just did that
Answer
6th of the power of 1 would be 5th power
Step-by-step explanation: