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4 years ago

Answere 4 and 6 PLEASE show work

Mathematics

2 answers:

AnnZ [28]4 years ago

7 0

8 divided by 4=2
She has read 2 pages of the chapter.
2+3=5
The answer is 5

yKpoI14uk [10]4 years ago

7 0

#4
5 pages
Kosta read 1/4 which is 2 pages and Christina read 3 pages

#6
9 section

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Jody has 3 red marbles 7 blue marbles and 8 yellow marbles what is the ratio red to blue marbles

torisob [31]

Answer:

3/7

Step-by-step explanation:

The ratio is the number of red marbles and the number of blue marbles in a fraction, so the ratio would be 3/7

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4 years ago

14. What point is in the first quadrant?<br> a. (1,-2)<br> b. (-2.1)<br> C (1,2)<br> d. (-2,-1)

Viefleur [7K]

Mf- we need a picture

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3 years ago

Find the measure of unknown angle

Lemur [1.5K]

Answer:

Step-by-step explanation:

z = 102 degree (opposite angles of a parallelogram are equal)

z + x + 34 = 180 degree 9sum of adjacent angles of a parallelogram is 180 degree)

102 + x + 34 = 180

x = 180 - 136

x = 44 degree

y + 102 + x = 180 degree (sum of interior angles of a triangle is 180 degree)

y + 102 + 44 = 180

y = 180 - 146

y = 34 degree

3 0

3 years ago

Read 2 more answers

The area of triangle ABC is 1.89 square feet. The measure of side c is ______.

Feliz [49]

we are given

Area is 1.89

$A=40$

$b=2.8$

now, we can use area formula

$A=\frac{1}{2} c*b*sin(A)$

$1.89=\frac{1}{2} *c*2.8*sin(40)$

now, we can solve for c

we will get

$c=2.10023$ .............Answer

7 0

3 years ago

Assume that a company hires employees on Mondays, Tuesdays, or Wednesdays with equal likelihood.a. If two different employees ar

horsena [70]

Answer:

$P(A) = \frac{1}{9}$

$P(B) = \frac{1}{3}$

$P(C) = \frac{1}{729}$

Step-by-step explanation:

We know that:

Only employees are hired during the first 3 days of the week with equal probability.

2 employees are selected at random.

So:

A. The probability that an employee has been hired on a Monday is:

$P(M) = \frac{1}{3}$ .

If we call P(A) the probability that 2 employees have been hired on a Monday, then:

$P(A) =P(M\ and\ M)\\\\P(A)=( \frac{1}{3})(\frac{1}{3})\\\\P(A) = \frac{1}{9}$

B. We now look for the probability that two selected employees have been hired on the same day of the week.

The probability that both are hired on a Monday, for example, we know is $P(A) = \frac{1}{9}$ . We also know that the probability of being hired on a Monday is equal to the probability of being hired on a Tuesday or on a Wednesday. But if both were hired on the same day, then it could be a Monday, a Tuesday or a Wednesday.

$P(B) = \frac{1}{9} + \frac{1}{9} + \frac{1}{9}\\\\P(B) = \frac{1}{3}$ .

C. If the probability that two people have been hired on a specific day of the week is $3(\frac{1}{3}) ^ 2$ , then the probability that 7 people have been hired on the same day is:

$P(C) = (\frac{1}{3}) ^ 7 + (\frac{1}{3}) ^ 7 + (\frac{1}{3}) ^ 7\\\\P(C) = \frac{1}{729}$

D. The probability is $\frac{1}{729}$ . This number is quite close to zero. Therefore it is an unlikely bastate event.

6 0

3 years ago