All categories

3 years ago

Need help please help the middle one

Mathematics

2 answers:

serious [3.7K]3 years ago

8 0

A because its true i know because i did it in school in fourth grade

olganol [36]3 years ago

6 0

The answer for the middle one is A

You might be interested in

Pls help I can’t afford to get my phone taken away :,)

Nataliya [291]

Answer:what do you need help with

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Plz help me well mark brainliest if correct..............?

Annette [7]

Answer: b and c because of the asasability numeral

3 0

3 years ago

The circle will be enlarged by a scale factor of 4.

sertanlavr [38]

Answer:

The area of the new circle is $144\pi \ in^2$

Step-by-step explanation:

Given:

radius of the circle = 3 in.

we know that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared.

Let

z-----> the scale factor

x-----> the area of the enlarged circle

y-----> the area of the original circle

So;

$z^2= \frac{x}{y}$

In this problem we have

$z=4$ ----> the scale factor

The area of the original circle is equal to

$y = \pi r^2= \pi (3)^2= 9\pi \ in^2$

Now substituting value of y and solve for x we get;

$4^2=\frac{x}{9\pi}\\ \\x= 16\times9\pi= 144\pi \ in^2$

Hence Area of the new Circle is $144\pi \ in^2$

Also The area of the enlarged circle is 16 times the area of the original circle.

4 0

4 years ago

How much work is it to lift a 20. kg sack of potatoes vertically 6.5 m?

kicyunya [14]

Answer:

bsbeheheiebei2bh3jeibeiebebibeekhee

idhbeeieeu

8 0

3 years ago

Find the equation of the straight line which passes through the point (-1,3) and make intercept on x - axis as thrice that on y

Triss [41]

Answer:

$y = -\frac{1}{3}x + \frac{8}{3}$

Step-by-step explanation:

Given

$(x_1,y_1) = (-1,3)$

$Intercept\ on\ x-axis = Intercept\ on\ y-axis.$

Required

Determine the equation

First, we calculate the intercepts using:

$\frac{x}{a} + \frac{y}{b} = 1$

Where

b = Intercept on y axis.

a = Intercept on x axis.

From the question:

$a = 3b$

The equation becomes:

$\frac{x}{3b} + \frac{y}{b} = 1$

Multiply through by 3b

$x + 3y = 3b$

We have: $(x_1,y_1) = (-1,3)$

So:

$-1 + 3 * 3 = 3b$

$8 = 3b$

Make b the subject

$b = \frac{8}{3}$

Substitute $b = \frac{8}{3}$ in $x + 3y = 3b$ to get the equation

$x + 3y = 3 * \frac{8}{3}$

$x + 3y = 8$

Make 3y the subject

$3y = -x + 8$

Make y the subject

$y = -\frac{1}{3}x + \frac{8}{3}$

5 0

3 years ago