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Travka [436]
3 years ago
11

Hey guys hope that u all have a great night sleep

Mathematics
2 answers:
Andre45 [30]3 years ago
7 0
Aw thanks bro, you too!
nadya68 [22]3 years ago
5 0

Answer:much love

Step-by-step explanation:

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Select the correct answer.
galina1969 [7]

Answer:

<h2>C. 8 + 3i</h2>

Step-by-step explanation:

(9 + 6i) - (1 + 3i) = 9 + 6i - 1 - 3i = (9 - 1) + (6i - 3i) = 8 + 3i

8 0
3 years ago
You want to buy birthday hats, cards, and teddy bears for your best friends birthday party. You buy the products for wholesale p
Naya [18.7K]

Answer:

I will create a five by four matrix to indicate the costs of the products.  The matrix will have five vertical columns and four horizontal rolls.  The vertical columns will show the product categories and the total costs for all the products and decorations.  The horizontal rolls will show the product costs, the decoration costs, and the total costs for each product category.

The size and shape of the matrix will be 5 by 4 with squared boxes.

Step-by-step explanation:

Products/Costs         Hats         Cards      Teddy    Total Costs

Product costs           $2.50       $0.90       $3.10        $6.50

Decoration costs      $1.50       $0.60        $1.70        $3.80

Total costs               $4.00        $1.50       $4.80       $10.30

6 0
3 years ago
Which table represents a function?
yawa3891 [41]
B represents a function ✔️
7 0
2 years ago
I need help with this question
malfutka [58]

Answer:


Step-by-step explanation:


7 0
3 years ago
Assume that the terminal side of thetaθ passes through the point (negative 12 comma 5 )(−12,5) and find the values of trigonomet
zmey [24]

Answer:

\sin \theta = \dfrac{5}{13} and \sec \theta = -\dfrac{13}{12}

Step-by-step explanation:

Assume that the terminal side of thetaθ passes through the point (−12,5).

In ordered pair (-12,5), x-intercept is negative and y-intercept is positive. It means the point lies in 2nd quadrant.

Using Pythagoras theorem:

hypotenuse^2=perpendicular^2+base^2

hypotenuse^2=(5)^2+(12)^2

hypotenuse^2=25+144

hypotenuse^2=169

Taking square root on both sides.

hypotenuse=13

In a right angled triangle

\sin \theta = \dfrac{opposite}{hypotenuse}

\sin \theta = \dfrac{5}{13}

\sec \theta = \dfrac{hypotenuse}{adjacent}

\sec \theta = \dfrac{13}{12}

In second quadrant only sine and cosecant are positive.

\sin \theta = \dfrac{5}{13} and \sec \theta = -\dfrac{13}{12}

6 0
3 years ago
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