Answer: (2,4)
Explanation: I hope this is what the question is asking for because I am in 9th grade hope this helps and I hope I am right
Answer:
33 1/3 percent smaller
Step-by-step explanation:
The number a exceeds the number b by 50 percent.
a = b + b*.5
a = b(1.5)
Divide by 1.5
a/1.5 = b
2/3a =b
We want to find (a-b)/a to find the percent decrease
(a-2/3a)/a *100percent
(1/3a)/a* 100 percent
1/3 * 100 percent
33 1/3 percent smaller
15+99x
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X+10<span>
10x – 1 remainder 5 </span>
(x+6)^(1/2)-5=x+1
(x+6)^(1/2)=x+6
((x+6)^(1/2))^2=(x+6)^2
x+6=x^2+12x+36
0=x^2+11x+30
(-11+(11^2-4(1)(30))^(1/2))/2
(-11+((1)^(1/2))/2
(-11+1)/2=-5
(-11-1)/2=-6
((-6)+6)^1/2-5=(-6)+1
(0^(1/2))-5=-5
-6 is non-extraneous
((-5)+6)^1/2-5=(-5)+1
(1^1/2)-5=-4
1-5=-4
-4=-4
-5 is non-extraneous