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Helga [31]
3 years ago
15

Plz help...................

Mathematics
2 answers:
Setler [38]3 years ago
8 0
To get the perimeter around a triangle, you simply add up all the lengths of the sides.

5x - 2 + 4x + 3 + 2x - 3

Then combine like terms.

5x - 2 + 4x + 3 + 2x - 3 = 11x - 2

So, 11x - 2 is the answer.
Kazeer [188]3 years ago
6 0
The answer is C, 11x-2
You might be interested in
Which is bigger, 7/8" or 9/16"?
Iteru [2.4K]
7/8 and 9/16

7*2/8*2 = 14/16

14/16 and 9/16

Now since we have a common denominator, we can compare the numerators.

14/16 is greater, so 7/8 is greater than 9/16

Answer: 7/8 is bigger
5 0
3 years ago
Read 2 more answers
An octagonal pyramid ... how many faces does it have, how many vertices and how many edges? A triangular prism ... how many face
nadezda [96]

1: 8 faces and 9 with the base 9 vertices and 16 edges

2: 3 faces and 5 with the bases 6 vertices and 9 edges

3: 3 faces and 4 with the base 4 vertices and 6 edges

Hope this can help you.

4 0
4 years ago
What is the value of x?<br><br> Enter your answer, as a decimal, in the box.
Katarina [22]

Answer:

x=50.6cm

Step-by-step explanation:

Triangle MAB is similar to triangle MNP

Since the triangles are similar, the corresponding ratios are in the same proportion.

Therefore we can write the relation;

\frac{|MB|}{|MP|}=\frac{|MA|}{|MN|}


\frac{x}{72.6}=\frac{46.2-14}{46.2}


This implies that;

\frac{x}{72.6}=\frac{32.2}{46.2}


We multiply both sides by 72.6 to get


\frac{x}{72.6}\times 72.6=\frac{32.2}{46.2}\times72.6


\Rightarrow x=50.6


Hence the value of x is 50.6 cm



8 0
3 years ago
Read 2 more answers
Sample spaces For each of the following, list the sample space and tell whether you think the events are equally likely:
Schach [20]

Answer and explanation:

To find : List the sample space and tell whether you think the events are equally likely ?

Solution :

a) Toss 2 coins; record the order of heads and tails.

Let H is getting head and t is getting tail.

When two coins are tossed the sample space is {HH,HT,TH,TT}.

Total number of outcome = 4

As the outcome HT is different from TH. Each outcome is unique.

Events are equally likely since their probabilities \frac{1}{4} are same.

b) A family has 3 children; record the number of boys.

Let B denote boy and G denote girl.

If there are 3 children then the sample space is

{GGG,GGB,GBG,BGG,BBG,GBB,BGB,BBB}

The possible number of boys are 0,1,2 and 3.

Number of boys      Favorable outcome    Probability

           0                      GGG                        \frac{1}{8}

           1                    GGB,GBG,BGG          \frac{3}{8}

           2                   GBB,BGB,BBG           \frac{3}{8}

           3                       BBB                         \frac{1}{8}

Since the probabilities are not equal the events are not equally likely.

c)  Flip a coin until you get a head or 3 consecutive tails; record each flip.

Getting a head in a trial is dependent on the previous toss.

Similarly getting 3 consecutive tails also dependent on previous toss.

Hence, the probabilities cannot be equal and events cannot be equally likely.

d) Roll two dice; record the larger number

The sample space of rolling two dice is

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

Now we form a table that the number of time each number occurs as maximum number then we find probability,

Highest number        Number of times         Probability

           1                                   1                     \frac{1}{36}

           2                                  3                    \frac{3}{36}

           3                                  5                    \frac{5}{36}

           4                                  7                    \frac{7}{36}

           5                                  9                    \frac{9}{36}

           6                                  11                    \frac{11}{36}

Since the probabilities are not the same the events are not equally likely.

4 0
3 years ago
The Answers are:
Ainat [17]

Answer:

Step-by-step explanation:

prpobaly quadrent 4

8 0
3 years ago
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