Get n by itself in both inequalities
(This program doesn't allow for regular less than or greater than signs, so for the purposes of this problem I will be using less than or equal to (≤) and greater than or equal to (≥) signs)
Inequality 1:

Inequality 2:

Now that you have both of the n's by themselves, you can put the two inequalities together, like this

Just keep in mind that these are supposed to be regular less than signs
Answer: Time spent on Question C=3 9/10
Step-by-step explanation:
Total Time to do the entire quiz= 20 minutes
Time spent on Question A=10 7 /10 minutes
Time spent on Question B=5 2/ 5 minutes
Time spent on Question C=Total Time to do the entire quiz-(Time spent on Question A+Time spent on Question B)
20mins- (10 7 /10 +5 2/ 5)
20mins - ( 15 7+4 /10)
20mins - ( 15 11/10=16 1/10))
20mins -16 1/10
19 10/10 -16 1/10
Therefore Time spent on Question C= 3 9/10
We are given
Nancy bought an extra-large bag of 1,288 beads to make necklaces
When she got home, she found another bag with 784 beads in it
so, total number of beads =1288+784
total number of beads =2072
now, we have
For one necklace , 56 beads are required
so, 56 beads = 1 necklace

for 2072 beads


so,
number of necklaces she can make is 37..........Answer
Answer:
3 patients had all the three complaints
Step-by-step explanation:
Let U be the set of patients who reported at the hospital on that day
Let F be the set of patients who complained of fever
Let S be the set of patients who had stomach troubles
Let I be the set of injured patients
Then the given data can be written as:
- n(U) = n(F∪S∪I) = 100
- n(F) = 70
- n(S) = 50
- n(I) = 30
- n(F∩S) + n(S∩I) + n(I∩F) - 3×n(F∩S∩I) = 44
n(F∩S∩I) = ?
Using the formula for the cardinal number of union of three sets:
n(F∪S∪I) = n(F) + n(S) + n(I) - n(F∩S) - n(S∩I) - n(I∩F) + n(F∩S∩I)
100 = 70 + 50 + 30 - (44 + 3×n(F∩S∩I)) + n(F∩S∩I)
100 = 150 - 44 - 2×n(F∩S∩I)
2×n(F∩S∩I) = 106 - 100 = 6
<u>n(F∩S∩I) = 3</u>