<img src="https://tex.z-dn.net/?f=%5Clim_%7Bx%20%5Cto%20%2B%5Cinfty%7D%20%28%5Cfrac%7Bx%5E%7B2%7D-3x-1%20%7D%7Bx%5E%7B2%7D%20-4x

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2 years ago

%2B2%7D%20%29%5E%7B%5Cfrac%7Bx%7D%7B2%7D%20%7D" id="TexFormula1" title="\lim_{x \to +\infty} (\frac{x^{2}-3x-1 }{x^{2} -4x+2} )^{\frac{x}{2} }" alt="\lim_{x \to +\infty} (\frac{x^{2}-3x-1 }{x^{2} -4x+2} )^{\frac{x}{2} }" align="absmiddle" class="latex-formula">

Mathematics

2 answers:

Natalka [10]2 years ago

7 0

Step-by-step explanation:

I know but I m feeling bore

Effectus [21]2 years ago

6 0

I solved on my phone it was a easy question just used a calculator to write up the fraction and infinite etc

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There is enough fencing to surround the dog's play yard. The yard must have a perimeter of n more than 38 feet. The length of th

Ierofanga [76]

Answer:

Step-by-step explanation:

Let y = length of side parallel to the side with no fence

x = length of each of the other two sides

Then, y+2x = 64. So, y = 64-2x

Area = A = xy = x(64-2x)

The graph of the area function is a parabola opening downward with a highest point and with x-intercepts (0,0) and (32,0).

By the symmetry of the parabola, the x-coordinate of the maximum point lies halfway between the x-intercepts.

So, the area is maximized when x = 16 ft

y = 64 - 2x = 32 ft

Maximum area = xy = (16)(32) = 512 ft2

To maximize the area of the garden, the side of the fence parallel to the side of the house should be 32 ft long, and the other two sides should both have length 16 ft.

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Long N. answered • 10/06/16

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For the fixed given perimeter, the maximum area which can be obtained is a square.

So for 3 sides= 64 feet

one side = 64/3

The maximum area is 64/3*64/3 square feet