Find the Mean, Median, Mode and Range of each series. Mean: 126 ÷ 9 = 14 1) 6 , 12 , 8 , 4 , 16 , 16 , 6 , 16 , 9 93 ÷ 9 2) 13 ,
Nadya [2.5K]
Answer:
129-14 is 115 than minus 6 than add 12
Step-by-step explanation:
Answer:
Its y=1/2x +2(the second one)
Step-by-step explanation:
Im pretty sure its the radius of the circle....
Sorry if im wrong
The distribution function of the univariate random variable x is continuous at x if and only if , F (x) = P (X ≤ x)
Continuous univariate statistical distributions are functions that describe the likelihood that a random variable, say, X, falls within a given range. Let P (a Xb) represent the probability that X falls within the range [a, b].
A numerically valued variable is said to be continuous if, in any unit of measurement, whenever it can take on the values a and b. If the random variable X can assume an infinite and uncountable set of values, it is said to be a continuous random variable.
If X can take any specific value on the real line, the probability of any specific value is effectively zero (because we'd have a=b, which means no range). As a result, continuous probability distributions are frequently described in terms of their cumulative distribution function, F(x).
To learn more about univariated data
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a. 
× 
A
b. 
× 
A
c. 
A
The LED which would glow brightest is LED C with the greatest current and voltage
The LED which would be the most dim is LED B with low voltage and consequently low current.
<h3>How to determine the current</h3>
The formula for finding current
I = V/R
Where v = voltage
R = resistance
A. V = 12V
R = 4. 7 + 15 = 19. 7 kΩ = 19700 Ω in series
× A
B. V = 9V
R = 4. 7 + 1 = 4. 7 kΩ = 4700Ω in series
× A
C. V= 12V
1/R = 
= 
×
R = 
= 310. 56 Ω
A
It is important to note that the brightness of a bulb depends on both current and voltage depending on whether the bulb it is in parallel or series.
The LED which would glow brightest is LED C with the greatest current and voltage
The LED which would be the most dim is LED B with low voltage and consequently low current.
Learn more about Ohms law here:
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