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Darya [45]
3 years ago
8

Please Help :3 What is the slope of the line who's equation is -48 = 2x - 3y?

Mathematics
1 answer:
pav-90 [236]3 years ago
3 0
I hope i helped! ~ Best of Luck!~

Updated!

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What is 4 3/4 - 1/3 = in fraction form
pentagon [3]

Answer:

53/12

Step-by-step explanation:

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3 years ago
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Through: (3, 4), slope = -2​
sineoko [7]

Answer:

y = -2x - 2

Step-by-step explanation:

Slope-Intercept Form: y = mx + b

Points: (3, 4)

Slope: -2

y = -2x + b

4 = -2 ( 3 ) + b

4 = -6 + b

b = -2

y = -2x - 2

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An instructor who taught two sections of Math 161A, the first with 20 students and the second with 30 students, gave a midterm e
uranmaximum [27]

Answer:

<em>The answers are for option (a) 0.2070  (b)0.3798  (c) 0.3938 </em>

Step-by-step explanation:

<em>Given:</em>

<em>Here Section 1 students = 20 </em>

<em> Section 2 students = 30 </em>

<em> Here there are 15 graded exam papers. </em>

<em> (a )Here Pr(10 are from second section) = ²⁰C₅ * ³⁰C₁₀/⁵⁰C₁₅= 0.2070 </em>

<em> (b) Here if x is the number of students copies of section 2 out of 15 exam papers. </em>

<em>  here the distribution is hyper-geometric one, where N = 50, K = 30 ; n = 15 </em>

<em>Then, </em>

<em> Pr( x ≥ 10 ; 15; 30 ; 50) = 0.3798 </em>

<em> (c) Here we have to find that at least 10 are from the same section that means if x ≥ 10 (at least 10 from section B) or x ≤ 5 (at least 10 from section 1) </em>

<em> so, </em>

<em> Pr(at least 10 of these are from the same section) = Pr(x ≤ 5 or x ≥ 10 ; 15 ; 30 ; 50) = Pr(x ≤ 5 ; 15 ; 30 ; 50) + Pr(x ≥ 10 ; 15 ; 30 ; 50) = 0.0140 + 0.3798 = 0.3938 </em>

<em> Note : Here the given distribution is Hyper-geometric distribution </em>

<em> where f(x) = kCₓ)(N-K)C(n-x)/ NCK in that way all these above values can be calculated.</em>

7 0
3 years ago
Does the point (–3, 2) lie inside, outside, or on a circle with center (4, 0) and radius 5 units?
anastassius [24]

Answer:

The point (-3, 2) lies outside of the circle centered at (4, 0) with radius 5.

Step-by-step explanation:

The distance between two points (x₁, y₁) and (x₂, y₂) on the x-y plane can be calculated with:

√((x₁ - x₂)² + (y₁ - y₂)²)

So in this case, with the points (-3, 2) and (4, 0), the distance is:

√((-3 - 4)² + (2 - 0)²)

√(49 + 4)

√(53) ≈ 7.28

Since 7.28 > 5, the point (-3, 2) lies outside of the circle centered at (4, 0) with radius 5.

8 0
4 years ago
Which statements are correct interpretations of this graph?
ki77a [65]

3 boxes are filled every 4 min.

.75 boxes are filled per minute.

6 0
3 years ago
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