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Luda [366]
3 years ago
9

Round 9,912 to the nearest thousand. 10,000 9,910 9,000 9,900

Mathematics
2 answers:
Afina-wow [57]3 years ago
6 0

Answer: 10,000 because you round up to the thousands place

Ad libitum [116K]3 years ago
6 0

Answer:

10,000?

Step-by-step explanation:

Round 9,912 to the nearest thousand. 10,000 9,910 9,000 9,900

9,910 and 9,900 aren't even thousands to round to?

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This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive an
igomit [66]

Answer:

\frac{d}{dx}[f(x)+g(x)+h(x)] = \frac{9\cdot x^{8}}{\sqrt{1-x^{18}}} - 81\cdot x^{80}-2\cdot x

Step-by-step explanation:

This derivative consist in the sum of three functions: f(x) = 81\cdot \sin^{-1} x^{9}, g(x) = - x^{81} and h(x) = - x^{2}. According to differentiation rules, the derivative of a sum of functions is the same as the sum of the derivatives of each function. That is:

\frac{d}{dx} [f(x)+g(x) + h(x)] = \frac{d}{dx} [f(x)]+\frac{d}{dx} [g(x)] +\frac{d}{dx} [h(x)]

Now, each derivative is found by applying the derivative rules when appropriate:

f(x) = 81\cdot \sin^{-1} x^{9} Given

f'(x) = \frac{9\cdot x^{8}}{\sqrt{1-x^{18}}} (Derivative of a arcsine function/Chain rule)

g(x) = - x^{81} Given

g'(x) = -81\cdot x^{80} (Derivative of a power function)

h(x) = - x^{2} Given

h'(x) = -2\cdot x (Derivative of a power function)

\frac{d}{dx}[f(x)+g(x)+h(x)] = \frac{9\cdot x^{8}}{\sqrt{1-x^{18}}} - 81\cdot x^{80}-2\cdot x (Derivative for a sum of functions/Result)

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Step-by-step explanation:

I hope its right!!!

  1. use sin (opp/hyp)
  2. Plug in values so: sin45=x/2
  3. Switch the sin45 and x place, they are "equal" in a sense
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40. 24+26=50 41. I don't understand that one either what grade are you in?
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