Josh drove 410 miles using 20 gallons of gas . at this rate ,how many miles would he drive using 18 gallons of gas

Mathematics

2 answers:

Sergio039 [100]3 years ago

6 0

410/20=20.5
1 gallon=20.5 miles
18 gallons=20.5x18
=369 miles

NISA [10]3 years ago

5 0

Let's set up a ratio. 410 / 20 should be equal to x / 18, right? So the rate of miles per gallon in the first one is 20.5 miles per gallon. So therefore, when you have 18 gallons, that would be 20.5 * 18 which is 369.

If this helped please rate, thank, and give brainliest answer!

You might be interested in

Which statement regarding variable overhead variance analysis is true? The variable overhead efficiency variance is exactly the

Drupady [299]

Answer:

Step-by-step explanation:

6 0

3 years ago

PLZZ HELP! PLZ NO PLAGARISM!

arlik [135]

Answer: The area of Rhode Island is about 1,212 square miles

7 0

3 years ago

How to solve -d/6+12=-7

Delicious77 [7]

IF you are solving for d:

isolate the D, do the opposite of PEMDAS.

-d/6 + 12 = -7

(subtract 12 from both sides)

-d/6 + 12 (-12) = -7 (-12)

-d/6 = -19

(multiply 6 to both sides)

-d/6(6) = -19(6)

-d = -19(6)

-d = -144

-d/-1 = -144/-1

d = 144

hope this helps

6 0

3 years ago

Question 7

serg [7]

$\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}$

Given - a cone with volume 769?3 ft³ , having a height of 15 ft

To calculate - radius of the cone

We know that ,

$\bold{Volume \: of \: cone = \frac{1}{3}\pi \: r {}^{2} h }\\$

substituting the values in the formula stated above ,

$\bold{769.3 = \frac{1}{3} \times 3.14 \times r {}^{2} \times 15} \\ \\\bold{\implies r {}^{2} = \frac{769.3 \times 3}{3.14 \times 15} } \\ \\\bold{\implies r {}^{2} = \cancel\frac{2307.9}{47.1}} \\ \\\bold{ \implies \: r {}^{2} = 49} \\ \\ \bold{\implies \: r = 7 \: ft}$