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dexar [7]
3 years ago
15

Josh drove 410 miles using 20 gallons of gas . at this rate ,how many miles would he drive using 18 gallons of gas

Mathematics
2 answers:
Sergio039 [100]3 years ago
6 0
410/20=20.5
1 gallon=20.5 miles
18 gallons=20.5x18
=369 miles


NISA [10]3 years ago
5 0
Let's set up a ratio. 410 / 20 should be equal to x / 18, right? So the rate of miles per gallon in the first one is 20.5 miles per gallon. So therefore, when you have 18 gallons, that would be 20.5 * 18 which is 369. 

If this helped please rate, thank, and give brainliest answer!
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How to solve -d/6+12=-7
Delicious77 [7]
IF you are solving for d:

isolate the D, do the opposite of PEMDAS.

-d/6 + 12 = -7

(subtract 12 from both sides)

-d/6 + 12 (-12) = -7 (-12)

-d/6 = -19

(multiply 6 to both sides)

-d/6(6) = -19(6)

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hope this helps
6 0
3 years ago
Question 7
serg [7]

\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}

  • Given - <u>a </u><u>cone</u><u> </u><u>with </u><u>volume</u><u> </u><u>7</u><u>6</u><u>9</u><u>?</u><u>3</u><u> </u><u>ft³</u><u> </u><u>,</u><u> </u><u>having </u><u>a </u><u>height </u><u>of </u><u>1</u><u>5</u><u> </u><u>ft</u>

  • To calculate - <u>radius </u><u>of </u><u>the </u><u>cone</u>

We know that ,

\bold{Volume \: of \: cone =  \frac{1}{3}\pi \: r {}^{2}  h }\\

<u>substituting</u><u> </u><u>the </u><u>values </u><u>in </u><u>the </u><u>formula</u><u> </u><u>stated </u><u>above </u><u>,</u>

\bold{769.3 =  \frac{1}{3}  \times 3.14 \times r {}^{2}  \times 15} \\  \\\bold{\implies r {}^{2}  =  \frac{769.3 \times 3}{3.14 \times 15} } \\  \\\bold{\implies  r {}^{2}  =  \cancel\frac{2307.9}{47.1}}  \\  \\\bold{ \implies \: r {}^{2}  = 49} \\  \\ \bold{\implies \: r = 7 \: ft}

therefore ,

<u>radius </u><u>=</u><u> </u><u>7</u><u> </u><u>cm</u>

hope helpful ~

4 0
2 years ago
27^x = 9^x − 4 Question 1 options: x = 8 x = 4 x = −4 x = −8
Mariulka [41]

Answer:

x = -8

Step-by-step explanation:

Given the equation:

27^x=9^{x-4}

Note that

27=3^3\\ \\9=3^2,

then

27^x=(3^3)^x=3^{3x}\\ \\9^{x-4}=(3^2)^{x-4}=3^{2(x-4)}

Rewrite the equation as

3^{3x}=3^{2(x-4)},

then

3x=2(x-4)\\ \\3x=2x-8\\ \\3x-2x=-8\\ \\x=-8

4 0
3 years ago
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