about the second one... well, is a "fait accompli" that using the pythagorean theorem, if x = 8 and y = 5, the hypotenuse must be √(8² + 5²) = √(89), which is neither of those choices.
5, 8, 13 are no dice, namely 5² + 8² ≠ 13
25, 64, 17 is are no dice too, because 25² + 17² ≠ 64²
however, 5,12 and 13 are indeed a pythagorean triple
also is 39, 80, 89.
when looking for a pythagorean triple, recall that c² = a² + b².
so the longest leg is the sum of the square of the small ones.
so what you'd do is, check the small legs, square them, add them up, if they're indeed a pythagorean triple, they "must" add up to the longest leg.
Simplify the given expression as shown below
On the other hand,
Solving for y using the special triangle shown below
Thus,
Then,
The two sets of solutions are
<h2>Then, the four smallest positive solutions are</h2>
<h2>The answers are 1,5,13,17</h2>
Answer:
1:3
Step-by-step explanation:
First find the measure of radius for both circles:
Circle 1:
2 x pi x r = 123
r = 123 divided by 6.28 = 19.58
Circle 2:
2 x pi x r = 32
r = 32 divided by 6.28 = 5.09
So, Ratio:
5.09 : 19.58
Approximately 1:3 ( 6:18)
The slope-point form: y - y₁ = m(x - x₁).
The slope-intercept form: y = mx + b.
We have:
and the point (-5, 7)
therefore