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meriva
1 year ago
14

What where William total fixed variable expenses the first year of college

Mathematics
1 answer:
VARVARA [1.3K]1 year ago
8 0

Since the details are not available, we have provided an overview of William's total fixed and variable expenses for the first year of college.

<h3>What are college costs?</h3>

There are five categories of college costs.

These college costs include tuition, room and board, books and supplies, personal expenses, and transportation.

Some of the college costs like tuition and room and board may be relatively fixed.

This leaves expenses like books and suppliers, personal expenses, and transportation relatively variable.

Thus, William needs to control his variable college costs so that they do not exceed the student loan.

Learn more about college costs at brainly.com/question/11650418

#SPJ1

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4 purple balloons is the answer
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2 years ago
Solve for the given variable (see pic)
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27+a=32
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Juliet deposited $9,000 into her savings account. The bank offers 2% interest. She invests her money for 6 months. How much mone
frutty [35]

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9,000 ×(1+0.02)^6

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5 0
2 years ago
What is the standard form of the equation of a line for which the length of the normal segment to the origin is 8 and the normal
jeka57 [31]
Slope of line = tan(120) = -tan(60) = - &radic;3
Distance from origin = 8

Let equation be Ax+By+C=0
then -A/B=-&radic;3, or
B=A/&radic;3.
Equation becomes
Ax+(A/&radic;3)y+C=0

Knowing that line is 8 units from origin, apply distance formula
8=abs((Ax+(A/&radic;3)y+C)/sqrt(A^2+(A/&radic;3)^2))
Substitute coordinates of origin (x,y)=(0,0)  =>
8=abs(C/sqrt(A^2+A^2/3))
Let A=1 (or any other arbitrary finite value)
solve for positive solution of C
8=C/&radic;(4/3) => C=8*2/&radic;3 = (16/3)&radic;3

Therefore one solution is
x+(1/&radic;3)+(16/3)&radic;3=0
or equivalently
&radic;3 x + y + 16 = 0

Check:
slope = -1/&radic;3  .....ok
distance from origin
= (&radic;3 * 0 + 0 + 16)/(sqrt(&radic;3)^2+1^2)
=16/2
=8  ok.

Similarly C=-16 will satisfy the given conditions.

Answer  The required equations are
&radic;3 x + y = &pm; 16 
in standard form.

You can conveniently convert to point-slope form if you wish.




4 0
3 years ago
<img src="https://tex.z-dn.net/?f=y%3Dx%5E%7B2%7D%20%2B3" id="TexFormula1" title="y=x^{2} +3" alt="y=x^{2} +3" align="absmiddle"
Katena32 [7]

Answer:

The domain is (negative infinity, infinity) the range is [3. Infinity) y>=3

Step-by-step explanation:

The domain for all quadratic functions are (Negative infinity, infinity)

The range is the output values of the function 3, to infinity

6 0
3 years ago
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