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3 years ago

The difference between 9 thirty-seven and 8 thirty sevens

Mathematics

1 answer:

ella [17]3 years ago

3 0

937-837= ?

937-837=100

Hope i Helped:)

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Multiply. Check picture.

VashaNatasha [74]

The answer is $3x^4-13x^3-x^2-11x+6$ .

Solution:

Use algebraic identity: $a^m\times a^n=a^{m+n}$

For example: $x^2\times x=x^{2+1}=x^3$

Given expression $(x^2-5x+2)$ and $(3x^2+2x+3)$ .

To multiply these equations.

$(x^2-5x+2)\times(3x^2+2x+3)$

$=x^2(3x^2+2x+3)-5x(3x^2+2x+3)+2(3x^2+2x+3)$

$=(3x^4+2x^3+3x^2)+(-15x^3-10x^2-15x)+(6x^2+4x+6)$

$=3x^4+2x^3+3x^2-15x^3-10x^2-15x+6x^2+4x+6$

Combine like terms together.

$=3x^4+(2x^3-15x^3)+(3x^2-10x^2+6x^2)-15x+4x+6$

$=3x^4-13x^3-x^2-11x+6$

$(x^2-5x+2)\times(3x^2+2x+3)=3x^4-13x^3-x^2-11x+6$

Hence the answer is $3x^4-13x^3-x^2-11x+6$ .

3 0

3 years ago

If a solution has a ( OH- )= 8.6 × 10-5 what is the pOH

riadik2000 [5.3K]

POH is the -log [ OH- ]. Using this equation, simply find the -log of the OH- concentration to find the pOH:

pOH = - log ( 0.000086 ) = 4.07

6 0

3 years ago

What is the solution for r in the following system of equations?<br> 2x + 3y = 16<br> 2 + 2y = 10

klio [65]

Answer:

(2,4)

*View attached graph*

Step-by-step explanation:

2x + 3y = 16

2 + 2y = 10

-2 - 2

2y = 8

/2 /2

y = 4

2x + 3y = 16

2x + 3(4) = 16

2x + 12 = 16

- 12 - 12

2x = 4

/2 /2

x = 2

(x,y) -> (2,4)

Hope this helps!

8 0

2 years ago

Al Johnson is a word processor. He is paid $2.95 a page. A normal job has 600 pages and requires about 225 words per page. About

mezya [45]

$2.95 * 600 pages= $1,770

D is the answer

7 0

3 years ago

Read 2 more answers

Exercise 12.1.1: Coin flips and events. About A coin is flipped four times. For each of the events described below, express the

butalik [34]

Answer:

a $Pr = 0.25$

b $Pr = 0.50$

c $Pr = 0.1875$

Step-by-step explanation:

Given

$n = 4$ --- number of times

$r = 2$ --- faces of a coin

First, is to determine the sample size.

This is calculated as:

$Size =r^n$

$Size =2^4$

$Size =16$

Solving (a): First and last slip is head

This event is represented as:

$E=\{HHHH, HHTH, HTHH, HTTH\}$

The probability is calculated as:

$Pr = \frac{n(E)}{Size}$

$Pr = \frac{4}{16}$

$Pr = 0.25$

b) At least 2 consecutive flips that is heads.

This event is represented as:

$E=\{HHHH,HHHT,HHTH,HHTT,THHH,THHT,HTHH,TTHH\}$

The probability is calculated as:

$Pr = \frac{n(E)}{Size}$

$Pr = \frac{8}{16}$

$Pr = 0.50$

c) First is tail and at least 2 consecutive flips is head.

This event is represented as:

$E=\{THHH,THHT,TTHH\}$

The probability is calculated as:

$Pr = \frac{n(E)}{Size}$

$Pr = \frac{3}{16}$

$Pr = 0.1875$

8 0

2 years ago