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3 years ago

If LM = 41 – 2x and NP = 7x + 5, find LM.

Mathematics

1 answer:

sdas [7]3 years ago

4 0

LM = 41 - 2x , -41 = -2x , -41/-2 = x , x = 20.5 , LM = 41 - 2 (20.5) , LM = 41 - 41 , LM = 0 :) Hope this helped

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lys-0071 [83]

What are the questions??

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3 years ago

Tamara and Clyde got different answers when dividing 2x4 + 7x3 – 18x2 + 11x – 2 by 2x2 – 3x + 1. Analyze their individual work.

lys-0071 [83]

Note: As you may have unintentionally missed to add the different answers, based on which we had to check who solved correctly between Tamara and Clyda's work.

But, I am actually solving the expression and you must note that whoever (between Tamara and Clyda's work) may have got the same answer or match the answer with mine, would be the one who solved correctly.

Answer:

We conclude that whoever (between Tamara and Clyda's work) may have got the answer as $x^2+5x-2$ after dividing $2x^4\:+\:7x^3\:-\:18x^2\:+\:11x\:-\:2$ by $2x^2\:-\:3x\:+\:1$ , would be the one who solved it correctly.

Step-by-step explanation:

Considering the expression

$2x^4\:+\:7x^3\:-\:18x^2\:+\:11x\:-\:2$

Lets divide the expression by $2x^2\:-\:3x\:+\:1$

Solution Steps:

$\frac{2x^4+7x^3-18x^2+11x-2}{2x^2-3x+1}$

Factorizing

$2x^4+7x^3-18x^2+11x-2:\quad \left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)$

$\frac{\left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)}{2x^2-3x+1}$

Factorizing

$2x^2-3x+1:\quad \left(2x-1\right)\left(x-1\right)$

$\frac{\left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)}{\left(2x-1\right)\left(x-1\right)}$

$\mathrm{Cancel\:}\frac{\left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)}{\left(2x-1\right)\left(x-1\right)}:\quad x^2+5x-2$

$x^2+5x-2$

Thus,

$\frac{2x^4+7x^3-18x^2+11x-2}{2x^2-3x+1}=x^2+5x-2$

Therefore, we conclude that whoever (between Tamara and Clyda's work) may have got the answer as $x^2+5x-2$ after dividing $2x^4\:+\:7x^3\:-\:18x^2\:+\:11x\:-\:2$ by $2x^2\:-\:3x\:+\:1$ , would be the one who solved it correctly.

Keywords: expression, division

Learn more about expression division from brainly.com/question/1575482

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2 years ago

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What is an unbrocken part of a circle called

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Answer:

an unbroken part of a circle consisting of two points on the circle called the endpoints and all the points of the circle between them. arc. an arc of a circle whose points are on or in the interior of a central angle.

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A package of 5 crackers contains 205 Calories. How many Calories are in one cracker using a double number line

natulia [17]

Answer:

Step-by-step explanation:

since there are 205 calories in 5 crackers we can represent this as

205/5

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$\frac{x}{1} =\frac{205}{5}$

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x=41

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Number line:

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