How do you graph y=-3|x-3|+1

Criminal investigators use biometric matching for fingerprint recognition, facial recognition, and iris recognition. When matchi

expeople1 [14]

Answer:

This is an incomplete question.

Step-by-step explanation:

When we are "testing an hypothesis" there is a null hypothesis (H0) and and alternative hypothesis (Ha). We usually select the null hypothesis as the one we are intending to reject. For example in the present case the null hypothesis is

H0= the mean match score is 80.

And the alternative hypothesis:

Ha= the mean match score is greater than 80.

So, the above means that if H0 is true, the person will not be considered as a suspect of a crime, but is H0 is false and Ha is true, the person will be considered as a suspect.

When we are testing an hypothesis there different kind of erros that we can commit:

- Type I error: is the error that takes place when we reject H0 but it is actually true.

- Type II error: is the error associated to the situation in which we do not reject H0 when it is actually false.

- There are no error when we accept H0 and it is effectively true or when we reject H0 and it is false.

As in the statement there is no "following sentence" to decide if there is a Type I eror, Type II eror or neither, we only can explain as above.

7 0

3 years ago

What is the answer to this math problem?

Ludmilka [50]

Answer:

5

Step-by-step explanation:

the answer is 5 because it sounds good

5 0

3 years ago

The process that produces Sonora Bars (a type of candy) is intended to produce bars with a mean weight of 56 gm. A random sample

oksano4ka [1.4K]

Answer:

$t=\frac{55.82-56}{\frac{0.77}{\sqrt{49}}}=-1.636$

Step-by-step explanation:

Data given and notation

$\bar X=55.82$ represent the sample mean

$s=0.77$ represent the standard deviation for the sample

$n=49$ sample size

$\mu_o =56$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to determine if the mean is less than 56, the system of hypothesis would be:

Null hypothesis: $\mu \geq 56$

Alternative hypothesis: $\mu < 56$

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{55.82-56}{\frac{0.77}{\sqrt{49}}}=-1.636$

4 0

3 years ago

Pleaseee helpp me i got one down!!!<br> (zoom in to see more clear)

iris [78.8K]

These 4 options are correct.