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WITCHER [35]
3 years ago
13

What is 25+100=125-500

Mathematics
2 answers:
dem82 [27]3 years ago
3 0
This answer would be -375
Vinvika [58]3 years ago
3 0

Answer:

false

Step-by-step explanation:

lol u must be kidding cuz that question doesn't make sense

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A bag of 7 bouncy balls cost $9.80. What is the unit price?
Fittoniya [83]

Answer:

$1.40

Step-by-step explanation:

Unit = "1 value"

9.80/7 = 1.4

8 0
3 years ago
Answer this question please branliest going :) thanks
White raven [17]

Answer:

11/1 or 11

Step-by-step explanation:

hope this helps

3 0
3 years ago
What is -8 square root of 9 when simplified​
gregori [183]

Answer:

\large\boxed{-8\sqrt9=-24}

Step-by-step explanation:

\sqrt{a}=b\iff b^2=a\\\\\sqrt9=3\ \text{because}\ 3^2=9\\\\-8\sqrt9=-8(3)=-24

7 0
3 years ago
If x is equal to -6 which equality is true​
Papessa [141]

Answer:

-5 - 3x > 10

Step-by-step explanation:

x = -6

Plug in the x value for each inequality:

-5 - 3(-6) > 10

-5 + 18 > 10

13 > 10

True

-3 - 5(-6) < -14

-3 + 30 < -14

27 < -14

False

1 - 2(-6) > 13

1 + 12 > 13

13 > 13

False

2 - (-6) < -3

2 + 6 < -3

8 < -3

False

Only one of these is true; that is the answer.

8 0
3 years ago
3x - 5y = 14 and – 2x + 2y = 0
zubka84 [21]

Answer:

x=5.6

y=-5.6

Step-by-step explanation:

3x - 5y = 14 Equation 1

– 2x + 2y = 0 Equation 2

Simultaneous equation can be solved either through elimination method or substitution method. But we use elimination method for this question

Multiply equation 1 by -2 (the coefficient of x in equation 2) and multiply equation 2 with 3 (the coefficient of x in equation 1), so that x will have the same coefficient in the new equations, and easy to eliminate

-2(3x - 5y = 14)

-6x+10y=-28 Equation 3

3(– 2x + 2y = 0)

-6x+6y=0 Equation 4

Subtract equation 4 from 3 to eliminate x

-6x+10y=-28

-6x+6y=0

-6x-(-6x)=-6x+6x=0

10y-6y=5y

-28-0=-28

5y=-28

y=-28/5

y=-5.6

Substitute for y in equation 2

– 2x + 2y = 0

– 2x + 2(-5.6) = 0

-2x-11.2=0

-2x=11.2

x=-11.2/2

x=5.6

7 0
3 years ago
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